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Full Discussion: Sum based on certain column
Top Forums UNIX for Dummies Questions & Answers Sum based on certain column Post 302834655 by radius on Friday 19th of July 2013 12:29:12 PM
Old 07-19-2013
i mean i want to sum value in column 3 based on column 6 and column 1

for example :
I have "X1" in column 6 and there are 2 rows with column 1 = 1/1/2013..then sum its value from column 3 ( 553.0763397 + 459.8333588 = 1012.9096985)

I have "X2" in column 6 and there is only one row with column 1= 1/1/2013..then sum its respected value from column 3 = 459.8333588

thanks
 

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DB2_RESULT(3)								 1							     DB2_RESULT(3)

db2_result - Returns a single column from a row in the result set

SYNOPSIS
mixed db2_result (resource $stmt, mixed $column) DESCRIPTION
Use db2_result(3) to return the value of a specified column in the current row of a result set. You must call db2_fetch_row(3) before calling db2_result(3) to set the location of the result set pointer. PARAMETERS
o $stmt - A valid stmt resource. o $column - Either an integer mapping to the 0-indexed field in the result set, or a string matching the name of the column. RETURN VALUES
Returns the value of the requested field if the field exists in the result set. Returns NULL if the field does not exist, and issues a warning. EXAMPLES
Example #1 A db2_result(3) example The following example demonstrates how to iterate through a result set with db2_fetch_row(3) and retrieve columns from the result set with db2_result(3). <?php $sql = 'SELECT name, breed FROM animals WHERE weight < ?'; $stmt = db2_prepare($conn, $sql); db2_execute($stmt, array(10)); while (db2_fetch_row($stmt)) { $name = db2_result($stmt, 0); $breed = db2_result($stmt, 'BREED'); print "$name $breed"; } ?> The above example will output: cat Pook gold fish Bubbles budgerigar Gizmo goat Rickety Ride SEE ALSO
db2_fetch_array(3), db2_fetch_assoc(3), db2_fetch_both(3), db2_fetch_object(3), db2_fetch_row(3). PHP Documentation Group DB2_RESULT(3)
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