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Full Discussion: What is wrong with: echo $PATH | sed s/:/\\n/g
Top Forums UNIX for Dummies Questions & Answers What is wrong with: echo $PATH | sed s/:/\\n/g Post 302833123 by alister on Tuesday 16th of July 2013 09:57:32 AM
Old 07-16-2013
Quote:
Originally Posted by marek
Code:
echo $PATH | sed 's/:/\n/g'
echo $PATH | sed 's/:/"\n"/g'
echo $PATH | sed 's/:/\\n/g'
echo $PATH | sed 's/:/"\\n"/g'
echo $PATH | sed "s/:/\n/g"
echo $PATH | sed "s/:/\\n/g"

hmm something wrong with my shell ...
No, There isn't. The problem is that you don't realize that most sed implementations do not support a \n escape sequence in the replacement text of a substitution command.

Quote:
Originally Posted by marek
Now lets try with a tab:

Code:
echo $PATH | sed 's/:/\t/g'
echo $PATH | sed 's/:/\\t/g'
echo $PATH | sed "s/:/\\t/g"
echo $PATH | sed "s/:/\t/g"

That means my shell has problems to interpret well the '\'
No. As with \n, most sed implementations do not support a \t escape sequence in the replacement text of a substitution command.

Quote:
Originally Posted by marek
No lets try your suggestion:

Code:
echo $PATH | sed "s/:/\
? /g"
sed: 1: "s/:/
/g": unescaped newline inside substitute pattern

This is due to how the shell treats a backslash at the end of a line within a double quoted string.

Quote:
Originally Posted by marek
same for 's ... '

Code:
echo $PATH | sed 's/:/\                                                                                 /g'
sed: 1: "s/:/
/g": unescaped newline inside substitute pattern

You made a mistake, because within single quotes, a backslash is not special and if it immediately precedes the newline then sed will be happy.

You should spend some time with both your shell and sed documentation.

Regards,
Alister

P.S. Above, when I say "most", I mean all except GNU sed.
 

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