Yes, the condition and action part is what I missed. However, when I did:
which worked fine!
How come like this? Thank you again!
When condition evaluates to true (non-empty string or non-zero arithmetic value), the action defaults to printing the current line. Since gsub() returns the number of substitutions performed and all of your input lines contained a space character; changing each space (by [:blank:] matching a space and then changing it to a space), got you what you wanted. Having the underscore in your regular expression is redundant since underscore is a punctuation character.
Try your script again when your input file contains an empty line (nothing but a newline) and a line that contains a single word with no leading or trailing spaces or punctuation to see the difference.
This User Gave Thanks to Don Cragun For This Post:
Hi all,
This problem has cost me half a day, and i still do not know how to do.
Any help will be appreciated. Thanks advance.
I want to use a variable as the first parameters of gsub function of awk.
Example:
{
...
arri]=gsub(i,tolower(i),$1)
(which should be ambraced by //)
...
} (1 Reply)
Hello,
I have a variable that displays the following results from a JVM....
1602100K->1578435K
I would like to collect the value of 1578435 which is the value after a garbage collection. I've tried the following command but it looks like I can't get the > to work. Any suggestions as... (4 Replies)
Hi all
I want to do a simple substitution in awk but I am getting unexpected output. My function accepts a time and then prints out a validation message if the time is valid. However some times may include a : and i want to strip this out if it exists before i get to the validation. I have shown... (4 Replies)
Hi,
Can some one please explain the following line please throw some light on the ones marked in red
awk '{print $9}' ${FTP_LOG} | awk -v start=${START_DATE} 'BEGIN { FS = "." } { old_line1=$0; gsub(/\-/,""); if ( $3 >= start ) print old_line1 }' | awk -v end=${END_DATE} 'BEGIN { FS="." } {... (3 Replies)
I want to replace comma with space and "*646#" with space.
I am using the following code:
nawk -F"|" '{gsub(","," ",$3); gsub(/\*646\#/"," ",$3);print}' OFS="|" file
I am getting following error:
Help is appreciated (5 Replies)
Hey,
I would like to replace a string by a new one. Teh problem is that both strings should be variables to be flexible, because I am having a lot of files (with the same structure, but in different folders)
for i in daysim_*
do
cd $i/5/
folder=`pwd |awk '{print $1}'`
awk '{ if... (3 Replies)
I must design a UNIX script to monitor files whose size is over a threshold of 5 MB in a specific UNIX directory
I meet a problem during the for loop in my script. Some file names contain spaces.
ls -lrt | awk '$5>=5000000 && length($8)==5 {gsub(/ /,"_",$9); print};'
-rw-r--r-- 1 was61 ... (2 Replies)
Hi, I want to print the first column with original value and without any double quotes
The output should look like
<original column>|<column without quotes>
$ cat a.txt
"20121023","19301229712","100397"
"20121023","19361629712","100778"
"20121030A","19361630412","100838"... (3 Replies)
Hi ALL,
I want to replace string occurrence in my file "Config" using a external file named "Mapping" using awk.
$cat Config
! Configuration file for RAVI
! Configuration file for RACHANA
! Configuration file for BALLU
$cat Mapping
ravi:ram
rachana:shyam
ballu:hameed
The... (5 Replies)
Discussion started by: useless79
5 Replies
LEARN ABOUT X11R4
regex
regex(1F) FMLI Commands regex(1F)NAME
regex - match patterns against a string
SYNOPSIS
regex [-e] [ -v "string"] [ pattern template] ... pattern [template]
DESCRIPTION
The regex command takes a string from the standard input, and a list of pattern / template pairs, and runs regex() to compare the string
against each pattern until there is a match. When a match occurs, regex writes the corresponding template to the standard output and
returns TRUE. The last (or only) pattern does not need a template. If that is the pattern that matches the string, the function simply
returns TRUE. If no match is found, regex returns FALSE.
The argument pattern is a regular expression of the form described in regex(). In most cases, pattern should be enclosed in single quotes
to turn off special meanings of characters. Note that only the final pattern in the list may lack a template.
The argument template may contain the strings $m0 through $m9, which will be expanded to the part of pattern enclosed in ( ... )$0 through
( ... )$9 constructs (see examples below). Note that if you use this feature, you must be sure to enclose template in single quotes so
that FMLI does not expand $m0 through $m9 at parse time. This feature gives regex much of the power of cut(1), paste(1), and grep(1), and
some of the capabilities of sed(1). If there is no template, the default is $m0$m1$m2$m3$m4$m5$m6$m7$m8$m9.
OPTIONS
The following options are supported:
-e Evaluates the corresponding template and writes the result to the standard output.
-v "string" Uses string instead of the standard input to match against patterns.
EXAMPLES
Example 1: Cutting letters out of a string
To cut the 4th through 8th letters out of a string (this example will output strin and return TRUE):
`regex -v "my string is nice" '^.{3}(.{5})$0' '$m0'`
Example 2: Validating input in a form
In a form, to validate input to field 5 as an integer:
valid=`regex -v "$F5" '^[0-9]+$'`
Example 3: Translating an environment variable in a form
In a form, to translate an environment variable which contains one of the numbers 1, 2, 3, 4, 5 to the letters a, b, c, d, e:
value=`regex -v "$VAR1" 1 a 2 b 3 c 4 d 5 e '.*' 'Error'`
Note the use of the pattern '.*' to mean "anything else".
Example 4: Using backquoted expressions
In the example below, all three lines constitute a single backquoted expression. This expression, by itself, could be put in a menu defini-
tion file. Since backquoted expressions are expanded as they are parsed, and output from a backquoted expression (the cat command, in this
example) becomes part of the definition file being parsed, this expression would read /etc/passwd and make a dynamic menu of all the login
ids on the system.
`cat /etc/passwd | regex '^([^:]*)$0.*$' '
name=$m0
action=`message "$m0 is a user"`'`
DIAGNOSTICS
If none of the patterns match, regex returns FALSE, otherwise TRUE.
NOTES
Patterns and templates must often be enclosed in single quotes to turn off the special meanings of characters. Especially if you use the
$m0 through $m9 variables in the template, since FMLI will expand the variables (usually to "") before regex even sees them.
Single characters in character classes (inside []) must be listed before character ranges, otherwise they will not be recognized. For exam-
ple, [a-zA-Z_/] will not find underscores (_) or slashes (/), but [_/a-zA-Z] will.
The regular expressions accepted by regcmp differ slightly from other utilities (that is, sed, grep, awk, ed, and so forth).
regex with the -e option forces subsequent commands to be ignored. In other words, if a backquoted statement appears as follows:
`regex -e ...; command1; command2`
command1 and command2 would never be executed. However, dividing the expression into two:
`regex -e ...``command1; command2`
would yield the desired result.
ATTRIBUTES
See attributes(5) for descriptions of the following attributes:
+-----------------------------+-----------------------------+
| ATTRIBUTE TYPE | ATTRIBUTE VALUE |
+-----------------------------+-----------------------------+
|Availability |SUNWcsu |
+-----------------------------+-----------------------------+
SEE ALSO awk(1), cut(1), grep(1), paste(1), sed(1), regcmp(3C), attributes(5)SunOS 5.10 12 Jul 1999 regex(1F)