You started with one process, then two processes that forked into 4 processes, three total fork calls. For the second fork, two were parents and two were children. Welcome to multiprocessing. Each process has its own copies of the variables. For instance if the first process was 1000, it forked off 1001 and then 1002, and 1001 forked off 1003.
Ok, this part I got.
But how come ?
One process wasn't supposed to fork another process.
-P0 forks P1 and both have i=2
- then only P1 does i++ because:
P1 is the forked child, who sees pid1==0 and P0 the father, who sees pid1>0
So, it means if(0) to P1 and if(true) to P0.
---
So far we have P0 with i=2 and P1 with i=3
-next step is:
For P1, the result of 3%3 will be 0,
so if ( 0 ) pid2 = fork();
and as far as I understood, P1 WONT FORK P2!!!
Instead, P0 will produce 2%3 == 2, so P0 will fork P2,
And we'll have only 3 processes.
Where is my mistake ?
---------- Post updated at 03:24 PM ---------- Previous update was at 03:19 PM ----------
Maybe because pid2 wasn't initialized ?
So when P0 tests pid2 and its value without being initialized is 0, P0 prints sea and mountain ?
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Consider the following piece of code:
int main(void) {
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