Hi,
I have a log file that I need to monitor as it's being written to, and I want to exclude certain strings from the output. At the moment I'm using ...
tail -f LogFileName_`date +%d`.log | egrep -v "First String To Exclude | 2nd string | 3rd string" ...which works OK - but now I need to... (1 Reply)
Hi all,
I know this question has probably been answered before, but I am struggling with this problem, even after googling a million pages.
In a file named rdmt.conf
I need a single character replaced, the number in the line below
CUR_OC4J_ID=1
It will always appear after... (3 Replies)
Can someone tell me how I can do this?
e.g:
Say file1.txt contains:
today is monday
the 22 of
NOVEMBER
2010
and file2.txt contains:
the
11th
month
of
How do i replace the word NOVEMBER with (5 Replies)
Can someone tell me how I can do this?
e.g:
a=$(echo -e wert trewt ertert ertert ertert erttert
erterte
rterter
tertertert
ert)
How do i replace the STRING with $a?
I try this:
sed -i 's/STRING/'"$a"'/g' filename.ext
but this don' t work (2 Replies)
QUESTION1:
How do you grep only an exact string. I am using Solaris10 and do not have any GNU products installed.
Contents of car.txt
CAR1_KEY0
CAR1_KEY1
CAR2_KEY0
CAR2_KEY1
CAR1_KEY10
CURRENT COMMAND LINE: WHERE VARIABLE CAR_NUMBER=1 AND KEY_NUMBER=1
grep... (1 Reply)
here is what i want to achieve... consider a file contains below contents. the file size is large about 60mb
cat dump.sql
INSERT INTO `table1` (`id`, `action`, `date`, `descrip`, `lastModified`) VALUES (1,'Change','2011-05-05 00:00:00','Account Updated','2012-02-10... (10 Replies)
I have a file example.txt as follows :SomeTextGoesHere
$$TODAY_DT=20140818
$$TODAY_DT=20140818
$$TODAY_DT=20140818I need to automatically update the date (20140818) in the above file, by getting the new date as argument, using a shell script.
(It would even be better if I could pass... (5 Replies)
Sorry for the long/weird title but I'm stuck on a problem I have. I have this XML file:
</member>
<member>
<name>TransactionID</name>
<value><string>123456789123456</string></value>
</member>
<member>
<name>Number</name>
... (9 Replies)
I have a file comp.pkglist which mention package version and release . In 'version change' and 'release change' line there are two versions 'old' and 'new' Version Change: --> Release Change: -->
cat comp.pkglist
Package list: nss-util-devel-3.28.4-1.el6_9.x86_64
Version Change: 3.28.4 -->... (1 Reply)
Discussion started by: Paras Pandey
1 Replies
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svk::log::filter::grep
SVK::Log::Filter::Grep(3) User Contributed Perl Documentation SVK::Log::Filter::Grep(3)SYNOPSIS
SVK::Log::Filter::Grep - search log messages for a given pattern
DESCRIPTION
The Grep filter requires a single Perl pattern (regular expression) as its argument. The pattern is then applied to the svn:log property
of each revision it receives. If the pattern matches, the revision is allowed to continue down the pipeline. If the pattern fails to
match, the pipeline immediately skips to the next revision.
The pattern is applied with the /i modifier (case insensitivity). If you want case-sensitivity or other modifications to the behavior of
your pattern, you must use the "(?imsx-imsx)" extended pattern (see "perldoc perlre" for details). For example, to search for log messages
that match exactly the characters "foo" you might use
svk log --filter "grep (?-i)foo"
However, to search for "foo" without regards for case, one might try
svk log --filter "grep foo"
The result of any capturing parentheses inside the pattern are not available. If demand dictates, the Grep filter could be modified to
place the captured value somewhere in the stash for other filters to access.
If the pattern contains a pipe character ('|'), it must be escaped by preceding it with a '' character. Otherwise, the portion of the
pattern after the pipe character is interpreted as the name of a log filter.
STASH /PROPERTY MODIFICATIONS
Grep leaves all properties and the stash intact.
perl v5.10.0 2008-08-04 SVK::Log::Filter::Grep(3)