Is there a command that sets a variable length?
I have a input of a variable length field but my output for that field needs to be set to 32 char.
Is there such a command?
I am on a sun box running ksh
Thanks (2 Replies)
Hi All,
Here is my original string: 192.168.2.1.8088. The target string I want: 192.168.2.1, how can I use awk or sed or other command to get rid of .8088 in the string?
Thanks,
Ray (9 Replies)
I have a file full of coordinates of the form:
37.68899917602539 58.07500076293945 57.79100036621094
The numbers don't always have the same number of decimal points. I need to reduce the decimal points of all the numbers (there are 128 rows of 3 numbers) to 2.
I have tried to do this... (2 Replies)
i am having a varialbe a , which is input to my file
i want to multiply this input with value .43, and assign it to variable b.
i tried it as below:
#!/bin/sh
a=$1
b=`expr $1\*0.43`
echo b=$b
error : expr: non-integer argument
Please tell me , how to do this.
Thanks (10 Replies)
Hi All,
I would like to set decimal point to 16 in the following bash script but it has syntax error at }:
awk '{printf"%.16e", (a<500,a++,$1/(a*1.1212121212121229e-02))}' input.dat >output.datHow may I set it in the correct way please? Thank you very much! (6 Replies)
Dear all,
I have a txt file with only one column which contains p values. My data looks like this:
5.04726976606584e-190
2.94065711152402e-189
2.94065711152402e-189
9.19932135717279e-176
1.09472516659859e-170
1.24974648916809e-170
0.1223974648916
0.9874974648916
...
what I want... (2 Replies)
Hi,
I have one input file which is delimited by pipe. I want to put decimal points in this input file at particular position in particular column and also get the negative sign (if any) at start of that column.
$ cat Input_file.txt
11|10102693|1|20151202|10263204|20151127|N|0001... (7 Replies)
Hi Team,
I have an issue to split the file which is having special chracter(German Char) using awk command.
I have a different length records in a file. I am separating the files based on the length using awk command.
The command is working fine if the record is not having any... (7 Replies)
Use and complete the template provided. The entire template must be completed. If you don't, your post may be deleted!
1. The problem statement, all variables and given/known data:
Is there a grep commands for numbers w/decimal points
Display lines for students with GPA above 3.69 but less... (3 Replies)
Discussion started by: jetoutant
3 Replies
LEARN ABOUT OSF1
look
look(1) General Commands Manual look(1)NAME
look - Finds lines in a sorted list
SYNOPSIS
look [-df] [-tcharacter] string [file]
The look command prints all lines in a sorted file that begin with string.
OPTIONS
Uses dictionary order; only letters, digits, tabs, and spaces are used in comparisons. Searches without regard to case; treats uppercase
and lowercase as equivalent. Ignores character and characters following it in the search string. If you specify look -tC ABCDE, the
string ABCDE would become (in effect) AB, with CDE being ignored. This option is primarily for shell scripts, in which more than one
string is being processed.
DESCRIPTION
If no file is specified, look searches in the system word list /usr/share/dict/words, with the options -df assumed by default.
The look command uses binary search.
The -d and -f options affect comparisons as in sort.
NOTES
In order to use the -f option, you must first sort file with the sort -f command; otherwise, look displays only lowercase items.
If you do not specify -f, but specify a file (such as /usr/share/dict/words) that has been sorted with sort -f, look may not produce any
output.
EXAMPLES
To search a sorted file called sortfile for all lines that begin with the string as, enter: look as sortfile To search the system word list
for all words beginning with smi, enter: look smi
This might result in: smile smirk smith smithereens Smithfield Smithson smithy smitten
FILES
System word list.
SEE ALSO
Commands: grep(1), sort(1), spell(1)look(1)