hi
i am trying to compare a value with value 50. but i am getting
"
I am using
if
then
echo "------------"
fi
please help
thanks in advance
Satya (2 Replies)
Im trying to fix my /etc/weekly that rotates various logs however it does them no matter what filesize they are and i want them to only do it if there file size exceeds 2M or something. So I'm playing with a script to get the filesize using a ls -l command which works and puts the value into a... (3 Replies)
Hello all, :confused:
I am not getting this error.
Pls help me.
./construct_operon.sh: line 5:
#!/bin/bash
# Construct Operons using gene pairs.
rm -rf operons_result
lines=`awk 'END {print NR}' ecoli_operons`
while ;
do
head -1 ecoli_operons | awk '{print $1"\n"$2}' > pattern
... (5 Replies)
find . -name "*.*"|xargs grep WT:DBF_WL>> $F
Wfexist=`cat $F|grep $i`
echo $Wfexist
if ;
then
echo $Wfexist
echo "Workflow Exist"
else
touch $O
chmod 777 $O
echo $Wfexist
echo $WfExist >> $O
fi
I am getting the error that -ne: unary operator expected in the line with red... (2 Replies)
I get the following error
./get_NE05: line 42:
while
do
echo ${STRING_NAME}
J=1
if ; then
EXT=0$I
else
EXT=$I
fi
while
do
echo $I-$J
#calculating last occurrence
OCCURRENCE=`grep -io "${STRING_NAME}"... (3 Replies)
i=0
while
Shell script reports an error "unary operator expected" pointing the above line.
$i by default is 0 and holds integer value and $buf is also holding integer value.
Please can some one let me know what is missing.
Thanks. (1 Reply)
Hiya all,
Why do I get a :unary operator expected when I try to put a condition statement in my shell script (sh) like so and how to fix?
if ; then
echo "say hello"
else
echo "don't say hello"
fi
? It seems if the script receives an argument it works but if I don't put an... (4 Replies)
Hi
I have problem with my script.
I dont now why but i don't change anything and script stop working.
this is my code:
#!/bin/sh
for i in `ps -A | grep pocron.sh | grep -v grep | awk '{print $2}'`
do
COUNT=$((COUNT+1))
done
ostatnie_wykonanie=`cat porader.log`... (1 Reply)
In all my Googling, this usually happens when someone is comparing a variable, and that variable is unset. That doesn't appear to be the case for me...
#!/bin/bash -x
while read line
do
f=$(echo $line | tr -s ' ' | cut -d' ' -f 3)
echo $f
if
then
echo "This... (2 Replies)
Discussion started by: jnojr
2 Replies
LEARN ABOUT PHP
mysql_fetch_row
MYSQL_FETCH_ROW(3) 1 MYSQL_FETCH_ROW(3)mysql_fetch_row - Get a result row as an enumerated arraySYNOPSIS
Warning
This extension is deprecated as of PHP 5.5.0, and will be removed in the future. Instead, the MySQLi or PDO_MySQL extension should
be used. See also MySQL: choosing an API guide and related FAQ for more information. Alternatives to this function include:
omysqli_fetch_row(3)
o PDOStatement::fetch
array mysql_fetch_row (resource $result)
DESCRIPTION
Returns a numerical array that corresponds to the fetched row and moves the internal data pointer ahead.
o $
result -The result resource that is being evaluated. This result comes from a call to mysql_query(3).
Returns an numerical array of strings that corresponds to the fetched row, or FALSE if there are no more rows.
mysql_fetch_row(3) fetches one row of data from the result associated with the specified result identifier. The row is returned as an
array. Each result column is stored in an array offset, starting at offset 0.
Example #1
Fetching one row with mysql_fetch_row(3)
<?php
$result = mysql_query("SELECT id,email FROM people WHERE id = '42'");
if (!$result) {
echo 'Could not run query: ' . mysql_error();
exit;
}
$row = mysql_fetch_row($result);
echo $row[0]; // 42
echo $row[1]; // the email value
?>
Note
This function sets NULL fields to the PHP NULL value.
mysql_fetch_array(3), mysql_fetch_assoc(3), mysql_fetch_object(3), mysql_data_seek(3), mysql_fetch_lengths(3), mysql_result(3).
PHP Documentation Group MYSQL_FETCH_ROW(3)
07-08-2013
