can anyone see the awk syntax error near line 1? I keep getting this error and I'm not familiar with awk very well yet so it is hard for me to see the errors.
fyi: deleteuser* refers to files in the directory where each one ends with a different date
ls -1 /mfupload/prod02/ftp/deleteuser* |... (12 Replies)
I generate a fullpath variable two different ways:
1) concat two variables rootpath and relpath to give me fullpath
2) use 'find' to get the fullpath
when I echo the variable, I get the same output for both. However,
I print the variable from method 1 in the below loop I get "awk syntax... (0 Replies)
hi there
i write one awk script file in shell programing
the code is related to dd/mm/yy to month, day year format
but i get an error
please can anybody help me out in this problem ??????
i give my code here including error
awk `
# date-month -- convert mm/dd/yy to month day,... (2 Replies)
Hi, I can't see what is wrong with the following command.
I am extracting a dollar amount (AMT_REJ, 6th field) from a comma delimited record and need to output it as numeric, removing the $sign and decimal point and output to another file. Everything seems to work except the $ sign which I need... (1 Reply)
Hi All,
I wrote a simple script.sh program
for i in seq (22)
do awk '$1==${i}' file1.txt|awk '{print $2}'> file${i}_study.txt
done
and then run it
%bash
%chmod +x script.sh
% ./script.sh
Give me error
awk: $1==${i}
awk: ^ syntax error
Do you have any idea why... (3 Replies)
Could somebody gently point out the error of my ways in the below (the flu I'm fighting might be contributing to my current haplessness)
awk -F="\t" \
'{
for (i = 1; i <= NR; i++);
FNR == i;
{
if (length($3) < 56 && length($1) > 56)
$1=($1" "$2); $2=$3; $3=$4;
... (1 Reply)
I know the below code worked, but the syntax appears to be wrong and I can not seem to correct it. Thank you :).
awk 'FNR==NR {E; next }>$3 in E {print $3, $5}' medical_exome__genes.txt RefSeqGene.txt > update.txt
awk: cmd. line:1: FNR==NR {E; next }>$3 in E {print $3, $5}
awk: cmd.... (2 Replies)
awk -F, ' NR>1 {
BEGIN{
chr=$2
}
END{
for (k in chr) {print k}
}
} ' $gene_file
I've a really simple code. I want to store gene name and it's chromosome and in the end print them.
I'm skipping line one as it contains headers.
But I don't know why I get error as: (2 Replies)
Discussion started by: genome
2 Replies
LEARN ABOUT DEBIAN
devel::refcount
Devel::Refcount(3pm) User Contributed Perl Documentation Devel::Refcount(3pm)NAME
"Devel::Refcount" - obtain the REFCNT value of a referent
SYNOPSIS
use Devel::Refcount qw( refcount );
my $anon = [];
print "Anon ARRAY $anon has " . refcount($anon) . " reference
";
my $otherref = $anon;
print "Anon ARRAY $anon now has " . refcount($anon) . " references
";
DESCRIPTION
This module provides a single function which obtains the reference count of the object being pointed to by the passed reference value.
FUNCTIONS
$count = refcount($ref)
Returns the reference count of the object being pointed to by $ref.
COMPARISON WITH SvREFCNT
This function differs from "Devel::Peek::SvREFCNT" in that SvREFCNT() gives the reference count of the SV object itself that it is passed,
whereas refcount() gives the count of the object being pointed to. This allows it to give the count of any referent (i.e. ARRAY, HASH,
CODE, GLOB and Regexp types) as well.
Consider the following example program:
use Devel::Peek qw( SvREFCNT );
use Devel::Refcount qw( refcount );
sub printcount
{
my $name = shift;
printf "%30s has SvREFCNT=%d, refcount=%d
",
$name, SvREFCNT($_[0]), refcount($_[0]);
}
my $var = [];
printcount 'Initially, $var', $var;
my $othervar = $var;
printcount 'Before CODE ref, $var', $var;
printcount '$othervar', $othervar;
my $code = sub { undef $var };
printcount 'After CODE ref, $var', $var;
printcount '$othervar', $othervar;
This produces the output
Initially, $var has SvREFCNT=1, refcount=1
Before CODE ref, $var has SvREFCNT=1, refcount=2
$othervar has SvREFCNT=1, refcount=2
After CODE ref, $var has SvREFCNT=2, refcount=2
$othervar has SvREFCNT=1, refcount=2
Here, we see that SvREFCNT() counts the number of references to the SV object passed in as the scalar value - the $var or $othervar
respectively, whereas refcount() counts the number of reference values that point to the referent object - the anonymous ARRAY in this
case.
Before the CODE reference is constructed, both $var and $othervar have SvREFCNT() of 1, as they exist only in the current lexical pad. The
anonymous ARRAY has a refcount() of 2, because both $var and $othervar store a reference to it.
After the CODE reference is constructed, the $var variable now has an SvREFCNT() of 2, because it also appears in the lexical pad for the
new anonymous CODE block.
PURE-PERL FALLBACK
An XS implementation of this function is provided, and is used by default. If the XS library cannot be loaded, a fallback implementation in
pure perl using the "B" module is used instead. This will behave identically, but is much slower.
Rate pp xs
pp 225985/s -- -66%
xs 669570/s 196% --
SEE ALSO
o Test::Refcount - assert reference counts on objects
AUTHOR
Paul Evans <leonerd@leonerd.org.uk>
perl v5.14.2 2011-11-15 Devel::Refcount(3pm)