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Full Discussion: Read statement not working
Top Forums Shell Programming and Scripting Read statement not working Post 302824993 by Don Cragun on Sunday 23rd of June 2013 12:08:02 AM
Old 06-23-2013
Quote:
Originally Posted by mohanalakshmi
hello guys,
i am having the below piece of code
Code:
error
()
{
echo"Press y /n"
read ans
case $ans in
y) main;;
n) exit
esac
}

In the abve code, read statement is not working i.e not waiting for user to enter input.
,i tested exit status its 1.
could anyone help me to do this

Thanks in advance
You haven't said what shell you're using, but assuming it is a shell that recognizes basic Bourne shell syntax you have several problems. You didn't mention that this script complained about an unknown error command and an unknown echoPress y /n command. Had used correct syntax for defining a function, you also need a main function or utility that is not shown in this code fragment. To get correct the syntax errors, try:
Code:
error() {
    echo "Press y/n"
    read ans
    case "$ans" in
        (y) main;;
        (n) exit;;
        (*) echo "Unexpected response: \"$ans\""
            exit 1;;
    esac
}

Although some of the changes here are editorial, the error() must appear on a single line with no space between the final "r" and the "()", and there must be a space after the echo.
 

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SHELL-QUOTE(1p) 					User Contributed Perl Documentation					   SHELL-QUOTE(1p)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)
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