|
|
Sponsored Content
Top Forums
Shell Programming and Scripting
Regex Question
Post 302821793 by john_prince on Saturday 15th of June 2013 01:59:29 PM
06-15-2013
|
|
10 More Discussions You Might Find Interesting
1. UNIX for Dummies Questions & Answers
hi,
i got a problem with understanding regular expressions. what i wanna do is
scanning the wtmp logfile for ips and if a specific ip is echoed id like to be a part of a text to be assigned to it.
the scanning is done with
#! /bin/bash
cat wtmp | strings | egrep -o "+\.+\.+\." | sort -u... (6 Replies)
Discussion started by: rocketkids
6 Replies
2. Shell Programming and Scripting
I have a simple file test.out that contains data in the form of
key1=A|shift1
key2=B|shift2
key3=C|shift3
and so on.
I need to get it to print
A
B
C
I can do it using lookbehind assertion such as this
( ?<==)()
yet I was wondering if there is another way of mutching single... (8 Replies)
Discussion started by: arushunter
8 Replies
3. Shell Programming and Scripting
Hi
I have a question on regex
There is a line in a script like
my_file="$(echo SunMonTueWed | sed "s//_&g") "
My question what does the expression _&g do.
Obviously in this example the output is
_Sun_Mon_Tue_Wed
Another question can i use some trick to get the result like... (3 Replies)
Discussion started by: xiamin
3 Replies
4. Shell Programming and Scripting
Hi, im sure this is really simple but i cant quite figure it out. how do i test against a word at the beginning of the line but up to the point of a delimiter i.e. ":"
for example if i wanted to test against the user in the /etc/passwd file
peter:x:101:100:peters account:/var/peter:/bin/sh
... (3 Replies)
Discussion started by: hcclnoodles
3 Replies
5. Shell Programming and Scripting
I have a basic question regarding * and . while using regex:
# echo 3 | grep ^*$
3
I think I understood why it outputs "3" here (because '*' matches zero or more of the previous character) but I don't understand the output of the following command:
# echo 3 | grep ^.$
#
I thought I... (7 Replies)
Discussion started by: mirage
7 Replies
6. UNIX for Dummies Questions & Answers
I have dates in mm/dd/yy format that I wish to convert to yy-mm-dd format.
()/()/() finds them, but when I try to replace with $3-$1-$2 both kate and kwrite treat it as a text literal. (2 Replies)
Discussion started by: porphyry5
2 Replies
7. Shell Programming and Scripting
Hi,
I am trying to write a regex for myscript and need some input from experts.
here is what I must grep for
TICKET{Sapce}{Space}{hyphen}
so here is the example data
TICKET 34554, CT-12345, TICKET 12345: some text here
TICKET 2342, CT-12345, MA-12344: some text here
TICKET... (5 Replies)
Discussion started by: rider29
5 Replies
8. Shell Programming and Scripting
Hi guys,
I have a file in the following format:
cmpr5551
cmpr6002
cmpr93
anne 5454
bbro 434
cmprsvc
cmprsvc7
ffgi55
vefe99
cmprsvc8
cmprsvc9
I need to "grep" only the entries which start with "cmpr" followed by the number. All other entries should be excluded.
I was trying to use... (3 Replies)
Discussion started by: aoussenko
3 Replies
9. Shell Programming and Scripting
Hi guys,
I am trying to "grep" or "egrep" the following entry out of the file using regex:
MACCDB1 or MACCDB2
The problem is that the file might contain other entries which start with "MACCDB" string.
I was trying to use regex to "grep" the exact pattern but it fails to output the correct... (2 Replies)
Discussion started by: aoussenko
2 Replies
10. Shell Programming and Scripting
I want to match all occurrence of 01,03,05,07,10,11 at 9th and 10th position of a string .
I tried the following but its also matching characters like 33 or 11 on 9th and 10th position .
sed "/^\{8\}00/d" A.TXT
000000001000
433483433339 <<< wrong
121121211100 <<< wrong
167710000110... (10 Replies)
Discussion started by: boncuk
10 Replies
LEARN ABOUT DEBIAN
paps
PAPS(1) General Commands Manual PAPS(1) NAME
paps - UTF-8 to PostScript converter using Pango SYNOPSIS
paps [options] files... DESCRIPTION
paps reads a UTF-8 encoded file and generates a PostScript language rendering of the file. The rendering is done by creating outline curves through the pango ft2 backend. OPTIONS
These programs follow the usual GNU command line syntax, with long options starting with two dashes (`-'). A summary of options is included below. --landscape Landscape output. Default is portrait. --columns=cl Number of columns output. Default is 1. Please notice this option isn't related to the terminal length as in a "80 culums terminal". --font=desc Set the font description. Default is Monospace 12. --rtl Do right to left (RTL) layout. --paper ps Choose paper size. Known paper sizes are legal, letter and A4. Default is A4. Postscript points Each postscript point equals to 1/72 of an inch. 36 points are 1/2 of an inch. --bottom-margin=bm Set bottom margin. Default is 36 postscript points. --top-margin=tm Set top margin. Default is 36 postscript points. --left-margin=lm Set left margin. Default is 36 postscript points. --right-margin=rm Set right margin. Default is 36 postscript points. --gutter-width=gw Set gutter width. Default is 40 postscript points. --help Show summary of options. --header Draw page header for each page. --markup Interpret the text as pango markup. --lpi Set the lines per inch. This determines the line spacing. --cpi Set the characters per inch. This is an alternative method of specifying the font size. --stretch-chars Indicates that characters should be stretched in the y-direction to fill up their vertical space. This is similar to the texttops behaviour. AUTHOR
paps was written by Dov Grobgeld <dov.grobgeld@gmail.com>. This manual page was written by Lior Kaplan <kaplan@debian.org>, for the Debian project (but may be used by others). April 17, 2006 PAPS(1)