Last week I was using the command:
' find /directory -mtime -2 -print' and it showed all the files modified within that period. However, now it only displays the directories and not the files modified. The only thing that changed is that I was granted access to some files.
Thanks (2 Replies)
I need to find out the last modified time for the files which are older than 6 months. If I use ls -l, the files which are older than 6 months, I am just getting the day, month and year instead of exact time. I am using Korn shell, and SUN OS.
Thanks in Advance,
Kiran (3 Replies)
Hi ,
I am trying to find out the List of files modified or added aftter installation of any component on SUN solaris box .
But i am not able to do it using ls or find command .
Can somebody help me out ?
Thanks
Sanjay Gupta (2 Replies)
Hi All,
I have a requirement to find out the files which are modified in the last 10 minutes.
I tried the find command with -amin and -mmin options, but its not working on my AIX server.
Can anyone of you could help me.
Thanks in advance for your help.
Raju (3 Replies)
Hi,
I want to modify a filename in AIX by attaching the last modified timestamp. I want the timestamp completely in numerical format (eg:200905081210. yr-2009, mnth - 05, date -08, hr - 12, mins - 10).
For example if the filename is a.log and it was modified on April 6th 2008 at 21.00. I... (16 Replies)
Hello,
I'm pretty stumped, and I don't know why I am not able to redirect the output to the 'graphme' file with the command below in Fedora 18.
tcpdump -l -n -t "tcp == 18" | perl -ane '($s,$j)=split(/,/,$F,2); print "$s\n";' > graphme
In case you're wondering, I was following the example... (2 Replies)
Need help reading file last modified date in format:
Filename (relative path);YYYYMMDDHHMMSS
And then write it back. My idea is to backup it to a text file to restore later.
Checked this command but does not work:
Getting the Last Modification Timestamp of a File with Stat
$ stat -f... (5 Replies)
This should recursively walk through all dirictories and
search for a specified string in all present files, if found
output manicured content (eg some regex) with CAT into
a specified directory (eg /tmp/)
one by one, keeping the original names
This is what I have so far, which seems to... (1 Reply)
Hi,
I would like use the output of my cut command as a variable in my following awk command. Here's what I've written.
cut -f1 info.txt | awk -v i=xargs -F'' '{if($6 == $i) print $20}' summary.txt
Where obviously the 'xargs' doesn't do what I want. How can I pass my cut result to my awk... (3 Replies)
Discussion started by: heyooo
3 Replies
LEARN ABOUT CENTOS
ksc
KSC(1) User Commands KSC(1)NAME
ksc - Linux kernel module source checker
SYNOPSIS
ksc [ -d | --directory ] DIRECTORY
ksc [ -k | --ko ] FILE
OPTIONS
KSC accepts command-line arguments, and has both a long and short form usage. You can use either style or combine them to specify
options. When the tool is run with kernel module sources it checks for all four architectures, and when run with binary kernel modules, it
checks for the specific architecture for which the binary was built.
Valid RHEL whitelist releases are rhel6.0, rhel6.1, rhel6.2, rhel6.3, rhel6.4
-h, --help
show this help message and exit
-c CONFIG, --config=CONFIG
path to the local ksc.conf file. If not specified the tool tries to read from ~/ksc.conf and if that is also not found then from
/etc/ksc.conf
-d DIRECTORY, --directory=DIRECTORY
path to the directory
-i, --internal
to create text files to be used internally.
-k KO, --ko=KO
path to the ko file. You should either use -d or -k to run the KSC tool, but not both. If both -d and -k option is used at the
same time then only -d is used and the -k option is discarded.
-n RELEASENAME, --name=RELEASENAME
Red Hat release against which the bug is to be filed. Default value is 6.5
-p PREVIOUS, --previous=PREVIOUS
path to the previous resultset file and submit it as a bug to Red Hat Bugzilla.
-r RELEASE, --release=RELEASE
RHEL whitelist release used for comparison
-s, --submit
Submits the report to the Red Hat bugzilla (https://bugzilla.redhat.com). The credentials need to be in the /etc/ksc.conf file. The
tool will prompt for bugzilla password.
The configuration file looks like below:
[bugzilla]
user=user@redhat.com
partner=partner-name
partnergroup=partner-group
server=https://bugzilla.redhat.com/xmlrpc.cgi
-v, --version
Prints KSC version number
ksc - Version 0.9.11 Feb 2014 KSC(1)