I know the command date +"%Y%m%d" can change today's date to digit format as below .
$date +"%Y%m%d"
20071217
it works fine .
now I want to do it back . If I have a file like below, (in the file , there are three lines, and each line have ; sign , after the ; sign is the date ) , I... (4 Replies)
I want to chnage the date format from the file format like below to
WT;T15D;0000007208;;20080401;3;0;0;3;;B;ZZZZZZ;
WT;T25D;0000007208;;20080401;6;0;0;6;;B;ZZZZZZ;
WT;T5D;0000007208;;20080401;123;0;0;123;;B;ZZZZZZ;
to
WT;T15D;0000007208;;04/01/200804;3;0;0;3;;B;ZZZZZZ;... (2 Replies)
Hi All,
this is my second post, last post reply was very helpful.
I have a data that has date in DD/MM/YYYY (07/11/2008) format i want to replace the backslash by a dot(.) so that my awk script can read it inside the C shell script that i have written.
i want to change 07/11/2008 to... (3 Replies)
dear members,
ls -l
drwxr-xr-x 40 root sys 1024 Jul 11 22:19 usr
drwxr-xr-x 43 root sys 1024 Feb 1 2009 var
i am using solaris 10
is that possibe to do
drwxr-xr-x 40 root sys 1024 25-08-2009 22:19 usr
drwxr-xr-x 43 root sys ... (4 Replies)
Hi guys,
I have a text file with lots of lines like this:
MCOGT23R27815 27/07/07 27/05/09
SO733AM0235 30/11/07 30/11/10
NL123403N 04/03/08 04/03/11
0747AM7474 04/04/08 04/04/11
I want to change each line so the date format looks like this:
MCOGT23R27815 07/07/27 09/05/27 ... (7 Replies)
Dear Friends,
Need your help once again,
I have a variable ( e.g. ${i}) whoch has date in MM/DD/YYYY (E.g. 12/31/2011) format.
I want to change it to DD/MM/YYYY (e.g. 31/12/2011) format.
Request you to guide me as we are unable to do the same.
Thanks in advance
Anu. (1 Reply)
Hi all,
I have a file that every line starts with the date and time. The format is like YYYYMMDDHHMM and I woulk like to change it to MM/DD/YY<space>HH:MM.
I tried to figure out a way to do it with sed, but I don't know how I could reorganize the digits of the first format. Does anyone have any... (1 Reply)
Hi,
I was looking for a script to change the date from one format to other. A search in the forum gave me the below script as a result.
#! /bin/ksh
format=YYYYMMDD
YEAR=${format%????}
DAY=${format#??????}
MON=${format#$YEAR}
MON=${MON%$DAY}
echo $MON/$DAY/$YEAR
I got it... (2 Replies)
Hi
I wish to change date from one format to another in unix.
eg: INPUT DATE: 2013159 (YEAR & NUMBER OF DAY)
OUTPUT DATE required: 20130608 (YYYYMMDD)
how to do it ?
Thanks in advance. (6 Replies)
Discussion started by: dashing201
6 Replies
LEARN ABOUT DEBIAN
mojo::date
Mojo::Date(3pm) User Contributed Perl Documentation Mojo::Date(3pm)NAME
Mojo::Date - HTTP 1.1 date container
SYNOPSIS
use Mojo::Date;
my $date = Mojo::Date->new(784111777);
my $http_date = $date->to_string;
$date->parse('Sun, 06 Nov 1994 08:49:37 GMT');
my $epoch = $date->epoch;
DESCRIPTION
Mojo::Date implements HTTP 1.1 date and time functions according to RFC 2616.
Sun, 06 Nov 1994 08:49:37 GMT ; RFC 822, updated by RFC 1123
Sunday, 06-Nov-94 08:49:37 GMT ; RFC 850, obsoleted by RFC 1036
Sun Nov 6 08:49:37 1994 ; ANSI C's asctime() format
ATTRIBUTES
Mojo::Date implements the following attributes.
"epoch"
my $epoch = $date->epoch;
$date = $date->epoch(784111777);
Epoch seconds.
METHODS
Mojo::Date inherits all methods from Mojo::Base and implements the following new ones.
"new"
my $date = Mojo::Date->new;
my $date = Mojo::Date->new($string);
Construct a new Mojo::Date object.
"parse"
$date = $date->parse('Sun Nov 6 08:49:37 1994');
Parse date in one of the following formats.
- Epoch format(784111777)
- RFC 822/1123 (Sun, 06 Nov 1994 08:49:37 GMT)
- RFC 850/1036 (Sunday, 06-Nov-94 08:49:37 GMT)
- ANSI C asctime() (Sun Nov 6 08:49:37 1994)
"to_string"
my $string = $date->to_string;
Render date suitable for HTTP 1.1 messages.
SEE ALSO
Mojolicious, Mojolicious::Guides, <http://mojolicio.us>.
perl v5.14.2 2012-09-05 Mojo::Date(3pm)