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Full Discussion: Shell Script Password Prompt
Homework and Emergencies Homework & Coursework Questions Shell Script Password Prompt Post 302816483 by vbe on Tuesday 4th of June 2013 04:39:14 AM
Old 06-04-2013
Ro make things easy to read, stick to one standard e.g. if you start with variables in UPPERCASE stick to it! That said that is what was the standard...
We like to say as first line something like:
Code:
#!/bin/sh
.
.

We then all know what shell is used for your script, which could be different then the one you use when connecting...

So

Code:
#!/yourshell
#
# Document  a little what the script is/for...
#

PASS="lux"
PASSCPT=0                           #  You need a counter for your loop...
#
# A little analyse of what is asked suggests you have a few ways to meet requirement
# You have to decide what you are to do:
# e.g. Load a string variable  with the reason of the prompt ( enter a passwd ...) can 
# be an elegant solution for it allows you to  also display how man chances are left at each loop execution...
#

read -p "Password: " MYPWD
echo ""

if [ "$MYPWD" = "$PASS" ] 
then
   echo "Password Accepted" 
   ls -l 

fi

And whatabout:
Quote:
If the password was typed correctly after it lists the files and folders in home directory it then needs to ask the name of the user and it inserts it and the date in the first and second lines of the file.
?
 

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SHELL-QUOTE(1)						User Contributed Perl Documentation					    SHELL-QUOTE(1)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.16.3 2010-06-11 SHELL-QUOTE(1)
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