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Top Forums Shell Programming and Scripting Error"syntax error at line 15: `end of file' unexpected" Post 302815111 by millan on Friday 31st of May 2013 03:47:35 AM
Old 05-31-2013
Error"syntax error at line 15: `end of file' unexpected"

While i m running below code, it is giving me the error"syntax error at line 15: `end of file' unexpected".

Pls let me know what is wrong here..i tried many ways, but no luck

Code:
 
dbSID="SWQE"
usrname="apps"
password="Wrgthrk3"
count=0
while [ $count -lt 3 ]
do
    sqlplus $usrname/$password@$dbSID <<-EOF 
    WHENEVER OSERROR EXIT 9;
    WHENEVER SQLERROR EXIT SQL.SQLCODE;
    prompt Connected to the database;
    quit;
    EOF
  count=`expr $count + 1`
done

 

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lpasswd(8)						      System Manager's Manual							lpasswd(8)

NAME
lpasswd - Change group or user password SYNOPSIS
lpasswd [OPTION]... [name] DESCRIPTION
Changes password of user or group name. If the name argument is not provided, username of the invoking user is used; the name argument is ignored if lpasswd is run set-uid to a different user. Entering an empty password (by pressing Enter) aborts the password setting operation. OPTIONS
-F, --plainpassword-fd=fd Read password from file descriptor fd, terminated by end of file, ' ' or ' '. -f, --password-fd=fd Read password hash from file descriptor fd, terminated by end of file, ' ' or ' '. -g, --group Change password of group name. By default the password of user name is changed. -i, --interactive Ask all questions when connecting to the user database, even if default answers are set up in libuser configuration. -P, --plainpassword=password Set the password to password. Note that the password can be viewed while running lpasswd using tools such as ps(1). -p, --password=encrypted Set the password to the password represented by the hash encrypted. Note that the hash can be viewed while running lpasswd using tools such as ps(1). EXIT STATUS
The exit status is 0 on success, nonzero on error. libuser Jan 12 2005 lpasswd(8)
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