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Top Forums Shell Programming and Scripting Print the column content based on the header Post 302813685 by Fundix on Tuesday 28th of May 2013 02:17:36 AM
Old 05-28-2013
Quote:
Originally Posted by millan
Hey Fundix,Thank you ..it worked fine.

But i want to keep name in a variable

var="name"
awk -F"," ' /$var/ { for (i=1;i<=NF;i++) if ($i=="$var") idx=i} $0 !~ /$var/ { print $idx} ' filename

But it is not giving the output..Could you pls tell me know how i will use a variable here.
You can use -v to pass vars to awk :

Code:
awk -v var="name" -F"," ' /var/ { for (i=1;i<=NF;i++) if ($i==var) idx=i} $0 !~ /var/ { print $idx} ' file

 

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DB2_FIELD_SCALE(3)							 1							DB2_FIELD_SCALE(3)

db2_field_scale - Returns the scale of the indicated column in a result set

SYNOPSIS
int db2_field_scale (resource $stmt, mixed $column) DESCRIPTION
Returns the scale of the indicated column in a result set. PARAMETERS
o $stmt - Specifies a statement resource containing a result set. o $column - Specifies the column in the result set. This can either be an integer representing the 0-indexed position of the column, or a string containing the name of the column. RETURN VALUES
Returns an integer containing the scale of the specified column. If the specified column does not exist in the result set, db2_field_scale(3) returns FALSE. SEE ALSO
db2_field_display_size(3), db2_field_name(3), db2_field_num(3), db2_field_precision(3), db2_field_type(3), db2_field_width(3). PHP Documentation Group DB2_FIELD_SCALE(3)
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