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Full Discussion: Print the column content based on the header
Top Forums Shell Programming and Scripting Print the column content based on the header Post 302813475 by kg_gaurav on Monday 27th of May 2013 11:23:03 AM
Old 05-27-2013
Code
Not tested but this should work
Code:
 
l=wc -l
l=`echo $l -1 |bc`
for name in `tail -$l $file|awk '{print $1}'|`
do
 tmp=`echo name|grep -Po '^[a-z]+$'`
 if [ "$tmp" = "$name" ]
  echo $name
 fi
done

way is simple. i tried reading file using tail (except the first line) and passed to awk. read the first column and using grep i tried matching it with a name formate which will contain charecters in range "a-z". it if matches -o opetion will return the matched part.
if it's name then it should return the complete name and tmp and name variable should match.
Hope i'm clear
 

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LEARN ABOUT POSIX

zgrep

ZGREP(1)						      General Commands Manual							  ZGREP(1)

NAME

       zgrep - search possibly compressed files for a regular expression

SYNOPSIS

       zgrep [ grep_options ] [ -e ] pattern filename...

DESCRIPTION

       Zgrep  invokes  grep  on  compressed  or  gzipped  files.   These  grep	options  will  cause  zgrep  to  terminate  with  an  error  code:
       (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*).  All other options specified are passed directly to grep.  If no file is specified,  then  the
       standard input is decompressed if necessary and fed to grep.  Otherwise the given files are uncompressed if necessary and fed to grep.

       If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.

EXIT CODE

       2 - An option that is not supported was specified.

AUTHOR

       Charles Levert (charles@comm.polymtl.ca)

SEE ALSO

       grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)

																	  ZGREP(1)
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