05-21-2013
@Yoda: Thanks for the input... just few months old to the world of Unix...
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1. Solaris
My input file looks like
"
@$SCRIPT/atp_asrmt_adj.sql
$SCRIPT/dba2000.scr -s / @$SCRIPT/cim1005w.pls
$SCRIPT/dba2000.scr -s / @$SCRIPT/cim1006w.pls
start $SCRIPT/cim1020d.sql;^M
spool $DATA/cim1021m.sql
@$DATA/cim1021m.sql
! rm $DATA/cim1021m.sql
spool $DATA/cim1021m.sql... (1 Reply)
Discussion started by: dowsed4u8
1 Replies
2. UNIX for Advanced & Expert Users
I have an input file which looks like
"
@$SCRIPT/atp_asrmt_adj.sql
$SCRIPT/dba2000.scr -s / @$SCRIPT/cim1005w.pls
$SCRIPT/dba2000.scr -s / @$SCRIPT/cim1006w.pls
start $SCRIPT/cim1020d.sql;^M
spool $DATA/cim1021m.sql
@$DATA/cim1021m.sql
! rm $DATA/cim1021m.sql
spool $DATA/cim1021m.sql... (6 Replies)
Discussion started by: dowsed4u8
6 Replies
3. Shell Programming and Scripting
Hi,
Please help me to extrat values b/w two delimiters.
$ echo $abc
i want to extract the value 12345 b/w %. (5 Replies)
Discussion started by: tsaravanan
5 Replies
4. Shell Programming and Scripting
I need to extract certain pieces from a string, wher delimiters may vary. For example
A0 B0 C0 12345677 X0 Y0 Z0
A1-B1 C1 12345678 X1 Y0 Z0
A1/B2 C77 12345679 X2 Y0 Z0
I need to get
C0 12345677 X0
C1 12345678 X1
C77 12345679 X2
I tried sed, see example below:
echo 'A0 B0... (2 Replies)
Discussion started by: migurus
2 Replies
5. Shell Programming and Scripting
Good afternoon!
I have an XML file from which I want to extract only certain elements contained within each line. The problem is that the format of each line is not exactly the same (though similiar). For example, oa_var will be in each line, however, there may be no value or other... (3 Replies)
Discussion started by: bab@faa
3 Replies
6. Shell Programming and Scripting
Basically , i want to delete strings of a particular pattern from the flat file which is " | " pipe delimited.
Below are the valid formats :
1) AAA (0) 111-111-111, AAA, BB
2) AAA (0) 111-111-1111;X, AAA, BB
original flat file example :
|ABC ABC XHAMK|AAA (0) 111-111-111, AAA,... (3 Replies)
Discussion started by: Ravi_007
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7. UNIX for Dummies Questions & Answers
Hi All,
How to Replace the delimiter for a particular field. I have used awk to replace the field values based on the position, but I tried to remove/replace delimiters with space on particular positions.
I tried tr command with combination of awk not sure if this is the correct way, but I am... (3 Replies)
Discussion started by: mora
3 Replies
8. Shell Programming and Scripting
Hi All,
I'm stuck-up in finding a way to skip the delimiter which come within double quotes using awk or any other better option. can someone please help me out.
Below are the details:
Delimited: |
Sample data: 742433154|"SYN|THESIS MED CHEM PTY.... (2 Replies)
Discussion started by: BrahmaNaiduA
2 Replies
9. Shell Programming and Scripting
Hello,
I would need to replace a delimiter in a flat file using.I would like to replace the semicolon (";") but only if it was contained in a string between quotes. For example:
Original flat file example:
abc;abc;"abc;abc";cd;"ef;ef";abc
aa;bb;"aa";cc;"ddd;eee";ff
Desired output:... (9 Replies)
Discussion started by: bartleby
9 Replies
10. Programming
I can find and replace text when the delimiters are unique. What I cannot do is replace text using two NON-unique delimiters:
Ex.,
"This html code <text blah >contains <garbage blah blah >. All tags must go,<text > but some must be replaced with <garbage blah blah > without erasing other... (5 Replies)
Discussion started by: bedtime
5 Replies
LEARN ABOUT DEBIAN
datetime::format::epoch::unix
DateTime::Format::Epoch::Unix(3pm) User Contributed Perl Documentation DateTime::Format::Epoch::Unix(3pm)
NAME
DateTime::Format::Epoch::Unix - Convert DateTimes to/from Unix epoch seconds
SYNOPSIS
use DateTime::Format::Epoch::Unix;
my $dt = DateTime::Format::Epoch::Unix->parse_datetime( 1051488000 );
# 2003-04-28T00:00:00
DateTime::Format::Epoch::Unix->format_datetime($dt);
# 1051488000
my $formatter = DateTime::Format::Epoch::Unix->new();
my $dt2 = $formatter->parse_datetime( 1051488000 );
$formatter->format_datetime($dt2);
DESCRIPTION
This module can convert a DateTime object (or any object that can be converted to a DateTime object) to the number of seconds since the
Unix epoch.
METHODS
Most of the methods are the same as those in DateTime::Format::Epoch. The only difference is the constructor.
o new()
Constructor of the formatter/parser object. It has no parameters.
SUPPORT
Support for this module is provided via the datetime@perl.org email list. See http://lists.perl.org/ for more details.
AUTHOR
Eugene van der Pijll <pijll@gmx.net>
COPYRIGHT
Copyright (c) 2003 Eugene van der Pijll. All rights reserved. This program is free software; you can redistribute it and/or modify it
under the same terms as Perl itself.
SEE ALSO
DateTime
datetime@perl.org mailing list
perl v5.10.1 2007-12-03 DateTime::Format::Epoch::Unix(3pm)