I'm trying to get a list of all users on the system, store the list in a variable, then find all the files of a certain extension owned by each of the users.
The command I use to get the list is
and this works just fine. However, if I try to store it in a variable, using
the list isn't complete. If I type
, I only get a fraction of the list.
hi
the code i ve written is as follows:
command="egrep ',100,|,200,' | wc -l"
count =`cat trial.txt | $command`
echo "$count"
the contents of
trial.txt is :
000,100,200,300,
001,200,100,201,
002,200,100,400,
i need to get the count using the command stored in a variable and using... (2 Replies)
Hi all,
I want to search for a data type in a line.For this in a loop i am checking for $DATA_TYPE in a line using grep.But grep is not able to find when i give this.
Can any one tell me how to check string in $DATA_TYPE variable in line usign grep (or) any other way to do the above task.
... (4 Replies)
Hi,
I want to write a perl script, which will increment number stored in file. I want to do this without any file handles. I think we have to use some UNIX commands. I am not sure how to do this with file handles.
Thanks, (1 Reply)
Hi all,
I have a variable say var1 (output from somewhere, which I can't change)which store something like this:
echo $var1
name=fred
age=25
address="123 abc"
password=pass1234
how can I make the variable $name, $age, $address and $password contain the info?
I mean do this in a... (1 Reply)
Greetings
So glad I found this forum!
I need to get a list of users in a variable so I can use "for" to iterate through them in a bash script.
I know this does not work, but I need to do something like this:
myusers=(cat /etc/passwd | cut -f1 -d )
for myuser in $myusers
do
... (2 Replies)
can anyone please help me with this:
i have written a shell script and a stored procedure which has one OUT parameter. now i want to use that out parameter as an input to the unix script but i am getting an error as variable not found. below are the unix scripts and stored procedure...
... (4 Replies)
I need help to store the value returned from the function to one variable and then use that variable.
PREVIOUS_DATE_FUNCTION()
{
date '+%m %d %Y' |
{
read MONTH DAY YEAR
DAY=`expr "$DAY" - 1`
case "$DAY" in
0)
MONTH=`expr "$MONTH" - 1`
case... (1 Reply)
Hi All,
I have below variable,
xyz=\$AI_XFR
Now, if you will run the below command
=> echo $xyz
$AI_XFR
It is returning hardcoded string value.
Whereas in environment, there is value in it. Like below:
=> echo $AI_XFR
/home/aditya/sandbox/xfr/
I need to resolve this... (4 Replies)
Hi,
I have a shell script where I have to connect t oracle database. I have to store the command in a variable and then run the command through the variable.The OS is solaris 10 and the shell is bash.pls help when I run the command it doesnot work.Thanks.
if
CONNECT= "sqlplus... (4 Replies)
Hi Forum.
I have the following challenge at work that I need to write a script for.
I have a file abc.txt with the following contents:
4560123456
4570987654
4580654321
I want to be able to search/replace in abc.txt - the first 4 characters anything starting with 4560 to 7777; 4570... (3 Replies)
Discussion started by: pchang
3 Replies
LEARN ABOUT LINUX
lpusers
lpusers(1M) System Administration Commands lpusers(1M)NAME
lpusers - set printing queue priorities
SYNOPSIS
lpusers -d priority-level
lpusers -q priority-level -u login-ID-list
lpusers -u login-ID-list
lpusers -q priority-level
lpusers -l
DESCRIPTION
The lpusers command sets limits to the queue priority level that can be assigned to jobs submitted by users of the LP print service.
The first form of the command (with -d) sets the system-wide priority default to priority-level, where priority-level is a value of 0 to
39, with 0 being the highest priority. If a user does not specify a priority level with a print request (see lp(1)), the default priority
level is used. Initially, the default priority level is 20.
The second form of the command (with -q and -u) sets the default highest priority-level (0-39) that the users in login-ID-list can request
when submitting a print request. The login-ID-list argument may include any or all of the following constructs:
login-ID A user on any system
system_name!login-ID A user on the system system_name
system_name!all All users on system system_name
all!login-ID A user on all systems
all All users on all systems
Users that have been given a limit cannot submit a print request with a higher priority level than the one assigned, nor can they change a
request that has already been submitted to have a higher priority. Any print requests submitted with priority levels higher than allowed
will be given the highest priority allowed.
The third form of the command (with -u) removes any explicit priority level for the specified users.
The fourth form of the command (with -q) sets the default highest priority level for all users not explicitly covered by the use of the
second form of this command.
The last form of the command (with -l) lists the default priority level and the priority limits assigned to users.
OPTIONS
The following options are supported:
-d priority-level
Set the system-wide priority default to priority-level.
-l
List the default priority level and the priority limits assigned to users.
-q priority-level
Set the default highest priority level for all users not explicitly covered.
-q priority-level -u login-ID-list
Set the default highest priority-level that the users in login-ID-list can request when submitting a print request.
-u login-ID-list
Remove any explicit priority level for the specified users.
EXIT STATUS
The following exit values are returned:
0 Successful completion.
non-zero An error occurred.
ATTRIBUTES
See attributes(5) for descriptions of the following attributes:
+-----------------------------+-----------------------------+
| ATTRIBUTE TYPE | ATTRIBUTE VALUE |
+-----------------------------+-----------------------------+
|Availability |SUNWpsu |
+-----------------------------+-----------------------------+
SEE ALSO lp(1), attributes(5)SunOS 5.10 19 Aug 1996 lpusers(1M)