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Top Forums Shell Programming and Scripting Why doesn't this Bash shell compile directories? Post 302806871 by murphy on Monday 13th of May 2013 07:52:02 PM
Old 05-13-2013
Quote:
Originally Posted by alister
In case you were commenting on the absence of a list, a bare for i is fine, since it defaults to in "$@".

Regards,
Alister
Thanks for the replys.

How would I make the argument the current working directory?

I thought
Code:
wd=$(pwd)

was the argument? The examples I have don't say anything about adding any extra code, and shoudl work, but obviously not..
 

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PWD(1)							    BSD General Commands Manual 						    PWD(1)

NAME
pwd -- return working directory name SYNOPSIS
pwd [-LP] DESCRIPTION
pwd writes the absolute pathname of the current working directory to the standard output. The following options are available: -L If the PWD environment variable is an absolute pathname that contains neither "/./" nor "/../" and references the current directory, then PWD is assumed to be the name of the current directory. -P Print the physical path to the current working directory, with symbolic links in the path resolved. The default for the pwd command is -P. pwd is usually provided as a shell builtin (which may have a different default). EXIT STATUS
The pwd utility exits 0 on success, and >0 if an error occurs. SEE ALSO
cd(1), csh(1), ksh(1), sh(1), getcwd(3) STANDARDS
The pwd utility is expected to be conforming to IEEE Std 1003.1 (``POSIX.1''), except that the default is -P not -L. BUGS
In csh(1) the command dirs is always faster (although it can give a different answer in the rare case that the current directory or a con- taining directory was moved after the shell descended into it). pwd -L relies on the file system having unique inode numbers. If this is not true (e.g., on FAT file systems) then pwd -L may fail to detect that PWD is incorrect. BSD
October 30, 2003 BSD
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