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Full Discussion: Output Row if Third Column is Larger
Top Forums Shell Programming and Scripting Output Row if Third Column is Larger Post 302806225 by alister on Sunday 12th of May 2013 10:04:22 PM
Old 05-12-2013
Quote:
Originally Posted by Scott
Simplest would be:
Code:
awk '$3>$2' File1

Quote:
Originally Posted by Don Cragun
Even for something this simple, I would still suggest /usr/xpg4/bin/awk, /usr/xpg6/bin/awk, or nawk instead of the default awk on a Solaris 5.10 system.
My paranoid nature would go further and explictly cast one of the operands with +0.

As far as I know, most awk implementations (if not all of them) will treat $3>$2 as a numeric comparison, but POSIX requires a locale-dependent string comparison.

Excerpts from POSIX awk:
Quote:
Each field variable shall have a string value or an uninitialized value when created.

...

A string value shall be considered a numeric string if it comes from one of the following:

1. Field variables

...

Comparisons (with the '<', "<=", "!=", "==", '>', and ">=" operators) shall be made numerically if both operands are numeric, if one is numeric and the other has a string value that is a numeric string, or if one is numeric and the other has the uninitialized value. Otherwise, operands shall be converted to strings as required and a string comparison shall be made using the locale-specific collation sequence.
$2 and $3 are both strings. If their string values are valid numbers, they are numeric strings. But, even if both are numeric strings, neither is a numeric. According to POSIX, for a numeric comparison at least one of the operands must be a numeric.

Even if no extant implementation adheres to this, an explicit cast is good future-proofing.

Regards,
Alister
Last edited by alister; 05-12-2013 at 11:11 PM..
 

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