Hi pasc,
In your first post in this thread, you said:
but that was a lie if you're getting the output:

Code:

SH1
SH2 SH3
SH4 SH5 SH6...

To get that output the files that contained SH2, SH4, and SH5 did not contain a line of text. By definition, a line contains a terminating newline character which is not present in those three files. Assuming that each of your input files contains exactly one line or exactly one partial line (missing a newline), try the following:
First, save the following in a file named cat1line

Code:

#!/bin/ksh
if [ $# -lt 2 ]
then    printf "Usage: %s output_file input_file...\n" "${0##*/}" >&2
        exit 1
fi
of="$1"
shift
> "$of"
while [ $# -gt 0 ]
do      (cat $1;echo)| {
                IFS="" read -r line
                printf "%s\n" "$line" >> "$of"
        }
        shift
done

Second, make it executable:

Code:

chmod +x cat1line

Third, run it:

Code:

./cat1line output_pathname *.sh