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Full Discussion: Pointer and address
Top Forums Programming Pointer and address Post 302803871 by yifangt on Tuesday 7th of May 2013 03:07:30 PM
Old 05-07-2013
Pointer and address

This code is to print out the program name and arguments list one by one:
Code:
  1 #include<stdio.h>
  2 
  3 void main(int argc, char *argv[])
  4 {
  5         int iCount = 0;
  6         while (iCount < argc) {
  7                 printf("argc:%d\t%s\n",iCount, argv[iCount]);
  8                 iCount++;
  9         }
 10 }
 11

I understand it is about pointer and pointer address of the array. Can somebody explain to me why line 7 should not be as :
Code:
printf("argc:%d\t%s\n",iCount, *argv[iCount]);

I thought *argv[iCount] is the correct way as argv[iCount] is one of the array members address, not the content of the pointer pointing to. But my understanding is wrong! What did I miss? Thanks a lot!

Last edited by yifangt; 05-07-2013 at 04:14 PM..
 

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ARG(2)								System Calls Manual							    ARG(2)

NAME
ARGBEGIN, ARGEND, ARGC, ARGF, arginit, argopt - process option letters from argv SYNOPSIS
#include <u.h> #include <libc.h> ARGBEGIN { char *ARGF(); Rune ARGC(); } ARGEND extern char *argv0; /* Alef only */ Arg *arginit(int argc, byte **argv); Rune argopt(Arg *arg); byte *argf(Arg *arg); DESCRIPTION
These macros assume the names argc and argv are in scope; see exec(2). ARGBEGIN and ARGEND surround code for processing program options. The code should be the cases of a C switch on option characters; it is executed once for each option character. Options end after an argu- ment --, before an argument -, or before an argument that doesn't begin with -. ARGC() returns the current option character. ARGF() returns the current option argument: a pointer to the rest of the option string if not empty, or the next argument in argv if any, or 0. ARGF must be called just once for each option that takes an argument. After ARGBEGIN, argv0 is a copy of argv[0] (conventionally the name of the program). After ARGEND, argv points at a zero-terminated list of the remaining argc arguments. Alef The Alef argument processing routines are unrelated. Instead, an aggr called Arg is initialized by a call to arginit. Successive calls to argopt return successive option characters, or zero at the end of the options. After a call to argopt, argf will return any argument string associated with the option. EXAMPLES
This C program can take option b and option f, which requires an argument. #include <u.h> #include <libc.h> void main(int argc, char *argv[]) { char *f; print("%s", argv[0]); ARGBEGIN { case 'b': print(" -b"); break; case 'f': print(" -f(%s)", (f=ARGF())? f: "no arg"); break; default: print(" badflag('%c')", ARGC()); } ARGEND print(" %d args:", argc); while(*argv) print(" '%s'", *argv++); print(" "); exits(0); } Here is the output for the run prog -bffile1 -r -f file2 arg1 arg2 prog -b -f(file1) badflag('r') -f(file2) 2 args: 'arg1' 'arg2' This Alef program accepts options b and, with an attached file name, f. #include <alef.h> void main(int argc, byte **argv) { int a, ac, bflag; byte *file; Arg *arg; arg = arginit(argc, argv); while(ac = argopt(arg)) switch(ac){ case 'b': bflag = 1; break; case 'f': file = argf(arg); break; } for(a=0; a<arg->ac; a++) print("argument %s ", arg->av[a]); } SOURCE
/sys/include/libc.h ARG(2)
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