I have the following error:
ls -lt | awk 'BEGIN NR > 1 { print $2, $9 }'
Syntax Error The source line is 1.
The error context is
BEGIN >>> NR <<< > 1 { print $2, $9 }
awk: 0602-500 Quitting The source line is 1.
What I want to do is ls a directory, skip the first... (3 Replies)
Hello,
I have the following command that does 2 searches.
awk '{if ($0 ~ /STRING1/) {c++} }{if ( c == 2 ) {sub(/STRING1/,"NEWSTRING") } } { print }' FILE
How do I search up after the first search?
thanks (4 Replies)
i have a little awk script that I use looks this:
awk '{if (FNR==1){print FILENAME; print $0}else print $0}' file1...file2....fi... > bundled.
i have completely forgotten how to unbundle this. I have tried several different approaches and still can not remember how to unbundle the file bundled.... (2 Replies)
I am trying to read through a file, gather the states in that file and change it from an abbreviation to the ful text.
Can anyone provide some assistance.
Thanks!! (4 Replies)
How I can rid of the following presentation du -sk /u*/oradata/TEST/*.dbf |awk '{print total+=$1} 1.28003e+06
4.35109e+06
4.36134e+06
4.4535e+06
5.47752e+06
5.48777e+06
7.52554e+06
7.73036e+06
9.06158e+06
:confused: thank you (3 Replies)
Can anyone help with this this one liner:
nawk -v RS='' '$1=$1' InputFile
What I have in the file:
0.0013985457223116
-0.0002338180925628
0.0
0.0003709430584958
-0.0005763523138347
0.0
And the output I want:
0.0013985457223116 -0.0002338180925628 0.0
0.0003709430584958... (1 Reply)
I have a script problem that I am not able to solve due my very limited understanding of unix/awk.
This is the contents of test.sh
awk '{print $1}'
From the prompt if I enter:
./test.sh Hello World
I would expect to see "Hello" but all I get is a blank line. Only then if I enter "Hello... (2 Replies)
Use and complete the template provided. The entire template must be completed. If you don't, your post may be deleted!
1. The problem statement, all variables and given/known data:
im using ls -l | xargs | awk '{what ever files here}'
im trying to get something that looks like this... (7 Replies)
Hi Experts,
I am trying to get system output to capture inside awk , but not working:
Please advise if this is possible :
I am trying something like this but not working, the output is coming wrong:
echo "" | awk '{d=system ("date") ; print "Current date is:" , d }'
Thanks, (5 Replies)
Discussion started by: rveri
5 Replies
LEARN ABOUT OSX
uri::url5.12
URI::URL(3) User Contributed Perl Documentation URI::URL(3)NAME
URI::URL - Uniform Resource Locators
SYNOPSIS
$u1 = URI::URL->new($str, $base);
$u2 = $u1->abs;
DESCRIPTION
This module is provided for backwards compatibility with modules that depend on the interface provided by the "URI::URL" class that used to
be distributed with the libwww-perl library.
The following differences exist compared to the "URI" class interface:
o The URI::URL module exports the url() function as an alternate constructor interface.
o The constructor takes an optional $base argument. The "URI::URL" class is a subclass of "URI::WithBase".
o The URI::URL->newlocal class method is the same as URI::file->new_abs.
o URI::URL::strict(1)
o $url->print_on method
o $url->crack method
o $url->full_path: same as ($uri->abs_path || "/")
o $url->netloc: same as $uri->authority
o $url->epath, $url->equery: same as $uri->path, $uri->query
o $url->path and $url->query pass unescaped strings.
o $url->path_components: same as $uri->path_segments (if you don't consider path segment parameters)
o $url->params and $url->eparams methods
o $url->base method. See URI::WithBase.
o $url->abs and $url->rel have an optional $base argument. See URI::WithBase.
o $url->frag: same as $uri->fragment
o $url->keywords: same as $uri->query_keywords
o $url->localpath and friends map to $uri->file.
o $url->address and $url->encoded822addr: same as $uri->to for mailto URI
o $url->groupart method for news URI
o $url->article: same as $uri->message
SEE ALSO
URI, URI::WithBase
COPYRIGHT
Copyright 1998-2000 Gisle Aas.
perl v5.12.5 2011-08-13 URI::URL(3)