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Top Forums Shell Programming and Scripting Creating a dictionary with domain name adjuncted Post 302802781 by gimley on Saturday 4th of May 2013 09:36:03 PM
Old 05-04-2013
Dear durden_tyler,
I tried this because when I created a perl script with both the
Code:
cat

and the subsequent part of the perl script, I got no result.
Sorry for hassling like this. I am a tyro in PERL and am still learning.
 

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CREATE TEXT SEARCH 
DICTIONARY(7) PostgreSQL 9.2.7 Documentation CREATE TEXT SEARCH DICTIONARY(7) NAME
CREATE_TEXT_SEARCH_DICTIONARY - define a new text search dictionary SYNOPSIS
CREATE TEXT SEARCH DICTIONARY name ( TEMPLATE = template [, option = value [, ... ]] ) DESCRIPTION
CREATE TEXT SEARCH DICTIONARY creates a new text search dictionary. A text search dictionary specifies a way of recognizing interesting or uninteresting words for searching. A dictionary depends on a text search template, which specifies the functions that actually perform the work. Typically the dictionary provides some options that control the detailed behavior of the template's functions. If a schema name is given then the text search dictionary is created in the specified schema. Otherwise it is created in the current schema. The user who defines a text search dictionary becomes its owner. Refer to Chapter 12, Full Text Search, in the documentation for further information. PARAMETERS
name The name of the text search dictionary to be created. The name can be schema-qualified. template The name of the text search template that will define the basic behavior of this dictionary. option The name of a template-specific option to be set for this dictionary. value The value to use for a template-specific option. If the value is not a simple identifier or number, it must be quoted (but you can always quote it, if you wish). The options can appear in any order. EXAMPLES
The following example command creates a Snowball-based dictionary with a nonstandard list of stop words. CREATE TEXT SEARCH DICTIONARY my_russian ( template = snowball, language = russian, stopwords = myrussian ); COMPATIBILITY
There is no CREATE TEXT SEARCH DICTIONARY statement in the SQL standard. SEE ALSO
ALTER TEXT SEARCH DICTIONARY (ALTER_TEXT_SEARCH_DICTIONARY(7)), DROP TEXT SEARCH DICTIONARY (DROP_TEXT_SEARCH_DICTIONARY(7)) PostgreSQL 9.2.7 2014-02-17 CREATE TEXT SEARCH DICTIONARY(7)
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