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Top Forums UNIX for Dummies Questions & Answers Any awk one liner to print df output? Post 302802047 by alister on Thursday 2nd of May 2013 09:02:17 PM
Old 05-02-2013
Quote:
Originally Posted by hanson44
[CODE]$ grep "\([89][0-9]\)%\|100%" input
\| is a GNU extension. There is no alternation operator in standard basic regular expression grammar. Outside of GNU (and Busybox, probably, since they explicitly model their implementation on GNU tools), I don't believe that will work anywhere.

Portable equivalents:
Code:
grep -e '[89][0-9]%' -e 100% file

... and ...
Code:
grep '[89][0-9]%
100%' file

Regards,
Alister

Last edited by alister; 05-02-2013 at 10:07 PM..
This User Gave Thanks to alister For This Post:
 

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