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Top Forums UNIX for Dummies Questions & Answers Grep to find lines matching given patern in a file Post 302801673 by Siva SQL on Thursday 2nd of May 2013 12:14:01 PM
Old 05-02-2013
Quote:
Originally Posted by zaxxon
Seems you are missing several dots in front of the stars, if you want to have any number of any type of character:
Code:
egrep '/app/oracle/build_lib/pkg32.*2012.*|/app/oracle/build_lib/pkg33.*2012.*' scj_drive_commands

The cat is not needed. grep takes a file as argument on it's own.
It is HP-Unix Environment.


I do not understand, why should we put . dot before * asterisk.

Last edited by Siva SQL; 05-03-2013 at 02:37 AM.. Reason: Given command is working
 

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ZGREP(1)						    BSD General Commands Manual 						  ZGREP(1)

NAME
zgrep, zegrep, zfgrep -- print lines matching a pattern in gzip-compressed files SYNOPSIS
zgrep [grep-flags] [--] pattern [files ...] zegrep [grep-flags] [--] pattern [file ...] zfgrep [grep-flags] [--] pattern [file ...] DESCRIPTION
zgrep runs grep(1) on files or stdin, if no files argument is given, after decompressing them with zcat(1). The grep-flags and pattern arguments are passed on to grep(1). If an -e flag is found in the grep-flags, zgrep will not look for a pattern argument. zegrep calls egrep(1), while zfgrep calls fgrep(1). EXIT STATUS
In case of missing arguments or missing pattern, 1 will be returned, otherwise 0. SEE ALSO
egrep(1), fgrep(1), grep(1), gzip(1), zcat(1) AUTHORS
Thomas Klausner <wiz@NetBSD.org> BSD
December 28, 2003 BSD
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