Difference of the same column when two other column matches and one column differs less than 1 hour Post: 302800575

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Top Forums Shell Programming and Scripting Difference of the same column when two other column matches and one column differs less than 1 hour Post 302800575 by Lakshmikumari on Tuesday 30th of April 2013 05:07:19 AM

04-30-2013

Registered User

Difference of the same column when two other column matches and one column differs less than 1 hour

This is my input file :

Code:

# cat list 20130430121600, cucm, location,76,2 20130430121600,cucm1,location1,76,4 20130430122000,cucm,location,80,8 20130430122000,cucm1,location1,90,8 20130430140000,cucm1,location1,87,11 20130430140000, cucm,location,67,9

This is the required output

Code:

20130430121600, cucm, location,76,2 20130430121600,cucm1,location1,76,4 20130430122000,cucm,location,4,8 20130430122000,cucm1,location1,14,8 20130430140000,cucm1,location1,87,11 20130430140000, cucm,location,67,9

Requirements :
The first column represents YYYYMMDDHHMISS - the date along with the time . The first row, first column represents 2013 year Apr 30 12th hour and 16 min.
I should take delta of 4th column between consecutive rows when 2nd and 3rd column matches, and also the difference between the 1st column is not more than 1 hour

In my list file, first and third row matches in 2nd and 3rd column, and also the difference between the time column is not more than 1 hour, and so I take a diff of the fourth column : 80 -76 =4.

https://www.unix.com/shell-programmin...#post302794979

This gave me a solution without the timestamp column.
Can some one help me out.

Thanks in Advance

---------- Post updated at 04:07 AM ---------- Previous update was at 04:02 AM ----------

Sending it again, as the csv file was not proper.
This is my input file :
20130430121600,cucm,location,76,2
20130430121600,cucm1,location1,76,4 20130430122000,cucm,location,80,8 20130430122000,cucm1,location1,90,8 20130430140000,cucm1,location1,87,11
20130430140000,cucm,location,67,9

This is the required output
20130430121600,cucm,location,76,2
20130430121600,cucm1,location1,76,4 20130430122000,cucm,location,4,8 20130430122000,cucm1,location1,14,8 20130430140000,cucm1,location1,87,11
20130430140000,cucm,location,67,9

Requirements :
The first column represents YYYYMMDDHHMISS - the date along with the time . The first row, first column represents 2013 year Apr 30 12th hour and 16 min.
I should take delta of 4th column between consecutive rows when 2nd and 3rd column matches, and also the difference between the 1st column is not more than 1 hour

In my list file, first and third row matches in 2nd and 3rd column, and also the difference between the time column is not more than 1 hour, and so I take a diff of the fourth column : 80 -76 =4.

https://www.unix.com/shell-programmin...#post302794979

This gave me a solution without the timestamp column.
Can some one help me out.

Thanks in Advance

Lakshmikumari

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db2_field_precision

DB2_FIELD_PRECISION(3)							 1						    DB2_FIELD_PRECISION(3)

db2_field_precision - Returns the precision of the indicated column in a result set

SYNOPSIS

       int db2_field_precision (resource  $stmt, mixed	$column)

DESCRIPTION

	Returns the precision of the indicated column in a result set.

PARAMETERS

	      o $stmt
		- Specifies a statement resource containing a result set.

	      o $column
		-  Specifies  the  column in the result set. This can either be an integer representing the 0-indexed position of the column, or a
		string containing the name of the column.

RETURN VALUES

	Returns an integer containing the precision of the specified  column.  If  the	specified  column  does  not  exist  in  the  result  set,
       db2_field_precision(3) returns FALSE.

SEE ALSO

       db2_field_display_size(3), db2_field_name(3), db2_field_num(3), db2_field_scale(3), db2_field_type(3), db2_field_width(3).

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