dear friends,
I have a large size file containg two fields data
like this
*** ****
122 222
***** *****
***** *****
232 233
i have file like this.
i want to remove blank lines from file .
i think awk is servive this problem
i wrote a awk command but the error is... (3 Replies)
Dear friends,
I am writing shell script in csh .
i want to make arthimatic operation in csh.
i wrote sysntax like this.
set val = 230
set tmp = `0.1 * $val + 300`
echo $tmp
but it is not working .
anyone please give me syntax. (3 Replies)
I am calculating a time and appending a space in front of it to get only certain records in a file because the times are represented in HH:II:SS format and I don't want to see anything other than the actual hour and minute combination (hence appending the space to the front of the time). My... (9 Replies)
Hey guys, i am having a problem in my query statement. I am using Mysql in Netbeans and c++.
What i am trying to do is for the user to enter a certain value and then the program will store the value into the database...
string NewMovie ;
Cout <<" Enter your new movie : " << endl ;
... (1 Reply)
Hi guys,
Basically I'm trying to write a CShell script that calls an awk script on a given directory (given in command-line). I keep getting a syntax error with my code though:
#!/bin/csh
set dir = $ARGV
foreach file ( $dir/* )
set output = 'awk -f /Desktop/aal $file'
echo... (3 Replies)
Hi Guys,
When below code is executed in script, I get desired output in output file.
awk 'NR >= $start_line && NR <= 3' master_scriptlist.txt > $driver1/scriptlist.txtBut when i replace 3 with a variable end_line=3, I do not get ouput. See code below. Is there any problem with syntax
awk... (6 Replies)
awk -v sw="lemons|dogs" 'NR>100 && NR<200 BEGIN { c=split(sw,a,""); } { for (w in a) { if ($0 ~ a) d]++; } }
END { for (i in a) { o=o (a"="(d]?d]:0)","); }
sub(",*$","",o); print o;
}' /home/jahitt/data.txt
what am i doing wrong with the above code? im pretty sure the issue is in the... (6 Replies)
Hi
Below script is throwing an error:
repos=root
filename=/home/admin/Desktop/authz
case $repos in
root)
root_folder="\"
do
sed "/$root_folder/a $username = $access" $filename
done
;;
esac
exit 0
Error:
./new1.sh: line 77: syntax error near unexpected token `do' (1 Reply)
Hi All,
I have a syntax problem with a procedure in oracle. I am looking to just produce the number of rows
from each table located in the HR schema nothing complex. This procedure works great up to dbms_output.put_line(tab_var); where it lists the names of each table in the user schema.
My... (5 Replies)
Discussion started by: bdby
5 Replies
LEARN ABOUT LINUX
shtool-path
SHTOOL-PATH.TMP(1) GNU Portable Shell Tool SHTOOL-PATH.TMP(1)NAME
shtool-path - GNU shtool command dealing with shell path variables
SYNOPSIS
shtool path [-s|--suppress] [-r|--reverse] [-d|--dirname] [-b|--basename] [-m|--magic] [-p|--path path] str [str ...]
DESCRIPTION
This command deals with shell $PATH variables. It can find a program through one or more filenames given by one or more str arguments. It
prints the absolute filesystem path to the program displayed on "stdout" plus an exit code of 0 if it was really found.
OPTIONS
The following command line options are available.
-s, --suppress
Supress output. Useful to only test whether a program exists with the help of the return code.
-r, --reverse
Transform a forward path to a subdirectory into a reverse path.
-d, --dirname
Output the directory name of str.
-b, --basename
Output the base name of str.
-m, --magic
Enable advanced magic search for ""perl"" and ""cpp"".
-p, --path path
Search in path. Default is to search in $PATH.
EXAMPLE
# shell script
awk=`shtool path -p "${PATH}:." gawk nawk awk`
perl=`shtool path -m perl`
cpp=`shtool path -m cpp`
revpath=`shtool path -r path/to/subdir`
HISTORY
The GNU shtool path command was originally written by Ralf S. Engelschall <rse@engelschall.com> in 1998 for Apache. It was later taken
over into GNU shtool.
SEE ALSO shtool(1), which(1).
18-Jul-2008 shtool 2.0.8 SHTOOL-PATH.TMP(1)