I think what viored didn't understand was how to get a and b into awk:
If $a and $b haven't already been set when you get to awk you can easily replace that first line with:
Does anybody have an explanation for the following:
The following scripts runs fine on IRIX64 6.5 but has bugs on Solaris 8.
#! /bin/sh
echo run only on an SGI machine
echo type in linenumber
read j
echo value
read value
awk -f rmspass2 level=$value $j'step1.mlf'
When the script is... (5 Replies)
Hi,
Is there any way to pass variable to a sed script.For awk we have -v option.like that do we have any way to pass variable to a sed script from a awk script or from normal script?
Thanx,
sounder (1 Reply)
Hi
I have a unix shell script with an awk statement. I would like to print some of the fields of an input file. However, I would like to print them dynamically, ie by passing the literal $1 $3 into the script to define the output.
I have tried the following:
variable1='$1'
awk... (2 Replies)
i have a file .NAMEexport MY_NAME=JOE
when i do this at the command prompt #. .NAME
$echo MY_NAME
$JOEi created a script called Run.sh . .NAME At the command prompt i did #sh Run.sh
#echo $MY_NAMEit returns nothing. What have i missed out? (7 Replies)
Hi all,
I have a shell script that sets up the environment for an application running on UNIX - ksh. This script is run using:
. ./script_name XX
where XX is a parameter. I want to run it from another shell script but when I do it I don't get the envornment variables set up and the prompt... (3 Replies)
HI all,
Very new to shell programming and just wanted some help on how to solve the following problem.
I have a small shell script which searches a given file and extracts some string parameters. I want to now be able to call this script from another shell script and somehow pass the parameters... (11 Replies)
Hi All,
I need to pass 2 variables name 'vamskt' and 'vamsi'.
Here is my question:
delete from gpi.usergroup where usg_user_id in ('vamskt');
delete from gpi.userroles where uro_user_id in ('vamskt');
delete from gpi.user where usr_id in ('vamskt');
insert into gpi.user... (3 Replies)
I'm trying to use awk to write new entries to a hosts file if they don't exist. I need to do so depending on the type of system I have. Below is what I have, but it isn't working.
awk -v myip1=$IP1 myip2=$IP2 myhost1=$HOST1 myhost2=$HOST2' BEGIN { mqhost1=0; mqhost2=0; stap1=0; stap2=0; }
... (4 Replies)
I have below data:
DAY1=10202013
I am trying below but not getting the desired output:
COUNT=1
DATE=DAY$COUNT
echo "Date is $DATE"
However output I am getting is:
Date is DAY1
I wanted the output as:
Date is 10202013
I tried following as well:
DAY1=10202013
COUNT=1... (3 Replies)
Trying to do so
echo "111:222:333" |awk -F: '{system("export TESTO=" $2)}'But it doesn't work (2 Replies)
Discussion started by: urello
2 Replies
LEARN ABOUT DEBIAN
igawk
IGAWK(1) Utility Commands IGAWK(1)NAME
igawk - gawk with include files
SYNOPSIS
igawk [ all gawk options ] -f program-file [ -- ] file ...
igawk [ all gawk options ] [ -- ] program-text file ...
DESCRIPTION
Igawk is a simple shell script that adds the ability to have ``include files'' to gawk(1).
AWK programs for igawk are the same as for gawk, except that, in addition, you may have lines like
@include getopt.awk
in your program to include the file getopt.awk from either the current directory or one of the other directories in the search path.
OPTIONS
See gawk(1) for a full description of the AWK language and the options that gawk supports.
EXAMPLES
cat << EOF > test.awk
@include getopt.awk
BEGIN {
while (getopt(ARGC, ARGV, "am:q") != -1)
...
}
EOF
igawk -f test.awk
SEE ALSO gawk(1)
Effective AWK Programming, Edition 1.0, published by the Free Software Foundation, 1995.
AUTHOR
Arnold Robbins (arnold@skeeve.com).
Free Software Foundation Nov 3 1999 IGAWK(1)