Hi,
I am trying to modify a script which accepts date in format dd/mm/yy. I am trying to modify the script so that it retrieves the date that was 15 days earlier from today as start date. Eg.if today is 05/09/2006, the script should retrieve 21/08/2006 as start date. Is there any script/code to... (2 Replies)
I want to get previous date from date command. I am using ksh shell.
Exmp:
today is 2008.09.04
I want the result : 2008.09.03
Please help.
Thanks in advance. (4 Replies)
Hi guys,
I had a scenario...
1. I had to get the previous days date in yyyymmdd format
2. i had to create a file with Date inthe format yyyymmdd.txt format
both are different
thanks guys in advance.. (4 Replies)
I have requirment to get last date of previous month and the first date of previous 4th month:
Example:
Current date: 20130320 (yyyymmdd)
Last date of previous month: 20130228 (yyyymmdd)
First date of previous 4th month: 20121101 (yyyymmdd)
In my shell --date, -d, -v switches are not... (3 Replies)
Legends,
i need to get previous day using date command.
Can you please help.
sdosanjh:/home> date +%m%d%y
011514
i tried -d '-1 day' but it is not working (5 Replies)
Hi all,
Need an urgent help on the below scenario.
script:
awk -F","
'BEGIN { #some variable assignment}
{ #some calculation and put values in array}
END {
year=#getting it from array and assume this will be 2014
month=#getting it from array and this will be 05
date=#... (7 Replies)
hi all,
I use
date +%Y
which gives Current year.
Requirement: I want previous year to be printed. Please help me.
Note: I tried
date +%d/%m/%Y -d "-1 years" which is not working. (10 Replies)
I am not able to fetch first date and last date previous month
date -d -1month +%Y-%m-%d
date -d -1month +%Y-%m-%d
I need two format dd-mm-yyy
previous month 01-03-2016
previous month 31-03-2016
and also only date 1 to 31
Aprriciate your replay (4 Replies)
Hi,
I am trying to add few (say 3 days) to sysdate using -
date -d '+ 3 days' +%y%m%d
and it works as expected.
But how to add few (say 3 days) to a literal date value and how bash treats a literal value as a date. Can we say just like in ORACLE TO_DATE that my given literal date value... (2 Replies)
Discussion started by: pointers1234
2 Replies
LEARN ABOUT PHP
datetime.setisodate
DATETIME.SETISODATE(3) 1 DATETIME.SETISODATE(3)DateTime::setISODate - Sets the ISO date
Object oriented style
SYNOPSIS
public DateTime DateTime::setISODate (int $year, int $week, [int $day = 1])
DESCRIPTION
Procedural style
DateTime date_isodate_set (DateTime $object, int $year, int $week, [int $day = 1])
Set a date according to the ISO 8601 standard - using weeks and day offsets rather than specific dates.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $year
- Year of the date.
o $week
- Week of the date.
o $day
- Offset from the first day of the week.
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
CHANGELOG
+--------+---------------------------------------------------+
|Version | |
| | |
| | Description |
| | |
+--------+---------------------------------------------------+
| 5.3.0 | |
| | |
| | Changed the return value on success from NULL to |
| | DateTime. |
| | |
+--------+---------------------------------------------------+
EXAMPLES
Example #1
DateTime.setISODate(3) example
Object oriented style
<?php
$date = new DateTime();
$date->setISODate(2008, 2);
echo $date->format('Y-m-d') . "
";
$date->setISODate(2008, 2, 7);
echo $date->format('Y-m-d') . "
";
?>
Procedural style
<?php
$date = date_create();
date_isodate_set($date, 2008, 2);
echo date_format($date, 'Y-m-d') . "
";
date_isodate_set($date, 2008, 2, 7);
echo date_format($date, 'Y-m-d') . "
";
?>
The above examples will output:
2008-01-07
2008-01-13
Example #2
Values exceeding ranges are added to their parent values
<?php
$date = new DateTime();
$date->setISODate(2008, 2, 7);
echo $date->format('Y-m-d') . "
";
$date->setISODate(2008, 2, 8);
echo $date->format('Y-m-d') . "
";
$date->setISODate(2008, 53, 7);
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2008-01-13
2008-01-14
2009-01-04
Example #3
Finding the month a week is in
<?php
$date = new DateTime();
$date->setISODate(2008, 14);
echo $date->format('n');
?>
The above examples will output:
3
SEE ALSO DateTime.setDate(3), DateTime.setTime(3).
PHP Documentation Group DATETIME.SETISODATE(3)