- Using date command, convert timestamp_supplied to seconds_since_epoch.
- For each line in log file (while read):
- Use cut or sed to get date_field.
- Using date command, convert date_field to seconds_since_epoch.
- Use test command to determine which seconds_since_epoch is larger.
Hi
From shell script i am invoking sqlplus to connect to oracle database and then i spool a csv file as with output. What i want to do is to change the file name with timestamp on it so after spooling finish shell script change file name with time stamp.
can someone help me to do that .
Thanks... (2 Replies)
I am trying to find a way to list every records inside a file (usually a log file) that are present after a record mathing/greater-then a timestamp supplied by another script.
The timestamp can be anywhere inside the record and it is usually in the standard `date` format (will not look for other... (5 Replies)
Hi,
Using sed awk or perl I am trying to do something similar to
https://www.unix.com/shell-programming-scripting/105887-sed-awk-concatenate-lines-until-blank-line-2.html
but my requirement is slightly different. What I am trying to accomplish is to reformat a logfile such that all lines... (4 Replies)
Hello. I'm not nearly good enough with awk/perl to create the logfile scraping script that my boss is insisting we need immediately. Here is a brief 3-line excerpt from the access.log file in question (actual URL domain changed to 'aaa.com'):
209.253.130.36 - - "GET... (2 Replies)
Hi all,
I have a tab-delimited text file of size 10Mb. I am trying to count the number of lines using,
grep -c . sample.txtor
wc -l < sample.txt or
awk 'END {print NR}' sample.txtAll these commands shows the count as 1, which means they are reading only the first header line of the file.... (3 Replies)
I need to be able to identify files with file timestamps greater than a given timestamp.
I am using the following solution, although it appears to compare files at the "seconds" granularity and I need it at the milliseconds. When I tested my solution, it missed files that had timestamps... (3 Replies)
Hi,
I have a process which outputs to a log.
Below is the code snippet:
process &> $LOGFILE&
The log file keeps on updating whenever a transaction is processed.
The log file has a time stamp added so every time I kill the process and start the process a new log file is... (4 Replies)
In unix systems I can call `file` to return me the file type.
file cel.vik
$ cel.vik: ASCII text
How can I append additional information when I create a file such that when I call `file` it returns me that additional information. (2 Replies)
Dear Experts,
I have a log file that contains a timestamp, I would like to filter record from that file based on timestamp. For example refer below file -
cat sample.txt
Jan 19 20:51:48 mukul-Vostro-14-3468 systemd: pam_unix(systemd-user:session): session opened for user root by (uid=0)... (6 Replies)
Discussion started by: mukulverma2408
6 Replies
LEARN ABOUT REDHAT
rearj
REARJ(1) Arj Software REARJ(1)NAME
rearj - Converts other archive formats to .arj files
SYNOPSIS
rearj [options] <!listfile(s)|filespec(s)|wildname(s)>
DESCRIPTION
The rearj command can repackage other archive formats to arj.
OPTIONS
-+ Ignore REARJ_SW variable.
-a[suffix]
Convert archives within archives ("*" for all formats).
-bcommand
Execute command before extracting files.
-ccommand
Execute command on extracted files before counting them.
-d Delete original archives.
-e No error switch.
-f Convert diskette archives.
-g Skip creation of output archive.
-i[name]
Check integrity of rearj program.
-j Skip if output archive size is larger than the original.
-k Skip archive timestamping.
-l[name]
Write append log file (default name is rearj.log).
-m[date]
Select archives before date in YYMMDDHHMMSS format.
-n[date]
Select archives on or after date in YYMMDDHHMMSS format.
-o Allow overwrite of existing target archive.
-p Ignore long filenames under Windows 95.
-q Query for each archive to convert.
-r Recurse through subdirectories.
-s Skip verify of file count and total size.
-tsuffix
Create suffix type archives.
-u[bak]
Allow update of archive with backup (default is BAK).
-v Execute configured command on extracted files.
-wdir Assign work directory.
-x[!]file
Exclude by filename, wildname, or listfile.
-y[text]
Delete output archive and write text to log (testing mode).
-z Simulate operation.
ENVIRONMENT
REARJ_SW If set, its value will be used as command line options.
EXIT STATUS
0 Success.
1 File not found.
2 File is not a configured archive type.
3 Target archive already exists.
4 Not enough disk space.
5 User skipped or user did not select update option.
6 UNPACK command error.
7 PACK command error.
8 Target cannot support directories.
9 Wrong file count.
10 Wrong total size.
11 Internal archive REARJ error.
12 Rename archive error.
13 Invoked -v command error (found a virus?).
14 Output archive is larger.
EXAMPLE
rearj * -r -d
Convert all archives to ARJ format, searching all subdirectories, deleting original archives.
SEE ALSO arj(1).
AUTHOR
This manual page was written by Ola Lundqvist <opal@debian.org> in pod format, then converted by Guillem Jover <guillem@debian.org> to
nroff format.
3.10 2003-03-10 REARJ(1)