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Full Discussion: Sort Files based on the number(s) on the file name
Top Forums UNIX for Dummies Questions & Answers Sort Files based on the number(s) on the file name Post 302795737 by dsedi on Thursday 18th of April 2013 09:19:37 AM
Old 04-18-2013
Quote:
Originally Posted by franzpizzo
It is not nice but it works

Code:
printf "mysample%d\n" $( ls -1 mysample*|sed 's/mysample//'| sort -n )

Thank you for the reply.. this is working

---------- Post updated at 09:17 AM ---------- Previous update was at 09:08 AM ----------

Quote:
Originally Posted by radoulov
Code:
printf '%s\n' mysample* | sort -k1.9n

Some ls implementations (the one from the GNU coreutils, for example) support the -v option (for natural sort of (version) numbers within text):

Code:
ls -v1 mysample*

For non-interactive use, drop the -1 option.
Thanks radoulov..
Code:
ls -v1 mysample*

didn't work for us.it said
Code:
ls: Not a recognized flag: v
Usage: ls [-1ACFHLNRSabcdefgiklmnopqrstuxEUX] [File...]

but as exepcted
Code:
printf '%s\n' mysample* | sort -k1.9n

working fine. Thanks for the help.

---------- Post updated at 09:19 AM ---------- Previous update was at 09:17 AM ----------

Quote:
Originally Posted by palanisvr
Code:
for i in `cat file`
do
fld1=`echo $i | tr -d '[0-9]'`
fld2=`echo $i | tr -d '[a-z]' |tr -d '[A-Z]'`
echo $fld1 " " $fld2 >> tmp.txt
sort  -n -k2 tmp.txt |awk -F ' ' '{print $1$2}'
rm -f tmp.txt
done

Thanks Palani.we Will try this.
 

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