sed not outputing variable into new file Post: 302795497

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Top Forums Shell Programming and Scripting sed not outputing variable into new file Post 302795497 by Don Cragun on Thursday 18th of April 2013 01:05:39 AM

04-18-2013

Registered User

If what you are trying to do is to create a directory and create a script (test3.sh) that is a copy of another script (test2.sh) with an mv command added after line 36 then I think the following does what you want. You haven't said what shell you're trying to use for this script, so I'm assuming a standards conforming shell such as ksh or bash. (I used ksh while I was testing this script.) Assuming that is correct, there are a couple of problems:

You can't have a minus sign in a function name. (I changed create-new to create_new to solve this problem.)
It is hard to get the quotes correct using sed to transform test2.sh into test3.sh. (In this case I found it much easier to use a here-document with ed instead of trying to get the editing command arguments specified correctly with sed.)
I added an additional case to provide a usage message (since I kept forgetting to add arguments while I was testing the script.
I added matching ('s to the cases in your switch because I use showmatch while editing scripts and I find it easier to read when I do that.

Anyway, does this do what you're trying to do?

Code:

#!/bin/ksh
bar=to #Added because the script needs a value for bar
foo=from #Added because the script needs a value for foo
me=${0##*/} #Added for use in the usage message
SHOW="$2"

create_new(){
        mkdir "$bar/$SHOW"
        ed -s test2.sh <<-EOF
                36a
                mv -v "$foo/$SHOW" "$bar/$SHOW/"
                .
                w test3.sh
        EOF
}

case "$1" in
        (create)
                create_new ;;
        (remote)
                remove ;;
        (*)     printf "Usage:\t%s create file\n\t%s remove Who Knows What\n" \
                        "$me" "$me" ;;
esac

If not, you're going to have to actually show us exactly what you want to appear in test3.sh rather than showing us the commands that you're using to create a test3.sh that does not contain what you want.

I also note that your script has a case "remote" that calls the undefined function "remove". I assume one of these is misspelled, but since you haven't given us any indication of what should happen when $1 is not "create", I left it as is.

Don Cragun

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wdmd

WDMD(8) 						      System Manager's Manual							   WDMD(8)

NAME

       wdmd - watchdog multiplexing daemon

SYNOPSIS

       wdmd [OPTIONS]

DESCRIPTION

       This  daemon opens /dev/watchdog and allows multiple independent sources to detmermine whether each KEEPALIVE is done.  Every test interval
       (10 seconds), the daemon tests each source.  If any test fails, the KEEPALIVE is not done.  In a standard configuration, the watchdog timer
       will  reset  the  system if no KEEPALIVE is done for 60 seconds ("fire timeout").  This means that if a single test fails 5-6 times in row,
       the watchdog will fire and reset the system.  With multiple test sources, fewer separate failures back to back can also cause a reset, e.g.

       T seconds, P pass, F fail
       T00: test1 P, test2 P, test3 P: KEEPALIVE done
       T10: test1 F, test2 F, test3 P: KEEPALIVE skipped
       T20: test1 F, test2 P, test3 P: KEEPALIVE skipped
       T30: test1 P, test2 F, test3 P: KEEPALIVE skipped
       T40: test1 P, test2 P, test3 F: KEEPALIVE skipped
       T50: test1 F, test2 F, test3 P: KEEPALIVE skipped
       T60: test1 P, test2 F, test3 P: KEEPALIVE skipped
       T60: watchdog fires, system resets

       (Depending on timings, the system may be reset sometime shortly before T60, and the tests at T60 would not be run.)

       A crucial aspect to the design and function of wdmd is that if any single source does not pass tests for the fire timeout, the watchdog	is
       guaranteed  to fire, regardless of whether other sources on the system have passed or failed.  A spurious reset due to the combined effects
       of multiple failing tests as shown above, is an accepted side effect.

       The wdmd init script will load the softdog module if no other watchdog module has been loaded.

       wdmd cannot be used on the system with any other program that needs to open /dev/watchdog, e.g. watchdog(8).

   Test Source: clients
       Using libwdmd, programs connect to wdmd via a unix socket, and send regular messages to wdmd to update an expiry time for their connection.
       Every test interval, wdmd will check if the expiry time for a connection has been reached.  If so, the test for that client fails.

   Test Source: scripts
       wdmd  will run scripts from a designated directory every test interval.	If a script exits with 0, the test is considered a success, other-
       wise a failure.	If a script does not exit by the end of the test interval, it is considered a failure.

OPTIONS

       --version, -V
		Print version.

       --help, -h
		Print usage.

       --dump, -d
		Print debug information from the daemon.

       --probe, -p
		Print path of functional watchdog device.  Exit code 0 indicates a
		functional device was found.  Exit code 1 indicates a functional device
		was not found.

       -D
		Enable debugging to stderr and don't fork.

       -H 0|1
		Enable (1) or disable (0) high priority features such as realtime
		scheduling priority and mlockall.

       -G name
		Group ownership for the socket.

       -S 0|1
		Enable (1) or disable (0) script tests.

       -s path
		Path to scripts dir.

       -k num
		Kill unfinished scripts after num seconds.

       -w path
		The path to the watchdog device to try first.

								    2011-08-01								   WDMD(8)