Originally Posted by Don Cragun

The script that you suggested will overwrite the output of all previously executed scripts with the output of the last script to run. The wait commands in your script don't do anything. (You didn't start the cmd* scripts asynchronously and it wouldn't make any difference if you did.) If you have some long running cmd* scripts, run this shell script in the background; not the jobs started by the script. You might want to try something like:

Code:

#!/bin/bash
i=1
while [ -f cmd$i ]
do      sh cmd$i > cmd$i_stdout.txt 2> cmd$i_stderr.txt
        i=$((i + 1))
done

Note that you specified that this is a bash script, but you're executing the cmd* scripts using sh (rather than bash). If the scripts to be run are executable scripts, you could omit the "sh" in red in the above script and let a #! line in each script specify the shell to be used for any script that doesn't want to use the system's default shell. This script will run any number of cmd* scripts as long as their names have consecutive integer values (starting with "1") at the ends of the names.

PS I didn't notice that you had used >> instead of > for later jobs, so you won't be overwriting the output. You may still want to consider the redirection methods shown above to separate stdout and stderr for each script into separate files. I also skipped the echoes you had showing the progression of scripts being executed. If you want them, I assume you know where to add them. (If not; let me know.)

Originally Posted by Don Cragun

The script that you suggested will overwrite the output of all previously executed scripts with the output of the last script to run. The wait commands in your script don't do anything. (You didn't start the cmd* scripts asynchronously and it wouldn't make any difference if you did.) If you have some long running cmd* scripts, run this shell script in the background; not the jobs started by the script. You might want to try something like:

Code:

#!/bin/bash
i=1
while [ -f cmd$i ]
do      sh cmd$i > cmd$i_stdout.txt 2> cmd$i_stderr.txt
        i=$((i + 1))
done

Note that you specified that this is a bash script, but you're executing the cmd* scripts using sh (rather than bash). If the scripts to be run are executable scripts, you could omit the "sh" in red in the above script and let a #! line in each script specify the shell to be used for any script that doesn't want to use the system's default shell. This script will run any number of cmd* scripts as long as their names have consecutive integer values (starting with "1") at the ends of the names.

PS I didn't notice that you had used >> instead of > for later jobs, so you won't be overwriting the output. You may still want to consider the redirection methods shown above to separate stdout and stderr for each script into separate files. I also skipped the echoes you had showing the progression of scripts being executed. If you want them, I assume you know where to add them. (If not; let me know.)