The number of results I get back will vary from computer to computer, don't I need to know the size of the array before I can use it?
---------- Post updated at 04:06 PM ---------- Previous update was at 03:58 PM ----------
I think I figured it out, but if someone has something better I would like to know. In the echo $OUTPUT line I can do whatever I want with the information.
Hi,
My code is as below:
integer i=7
while ((i <= 5 ));
do
# test_out is a variable which contains data separated by "^".
a= `echo $test_out | cut -d"^" -f$i`
echo "$a"
(( i = i + 1));
done
From the above code, i kept $i after f so that i can capture all the data which is... (1 Reply)
Hi folks,
I'm using bash and would like to do the following. I would like to read some values from the file and store it in the variable and use it.
My file is 1.txt and its contents are
VERSION=5.6
UPDATE=4
I would like to read "5.6" and "4" and store it in a variable in shell... (6 Replies)
i want to store the output of 'tail -5000 file' to a variable.
If i want to access the contents of that variable, it becomes kinda difficult because when the data is stored in the variable, everything is mushed together. you dont know where a line begins or ends.
so my question is, how can i... (3 Replies)
Hi all, im having snags creating a variable which uses commands like cut and grep. In the instance below im simply trying to take a value from another file and assign it to a variable. When i do this it only prints the $a rather than the actual value. I know its simple but does anyone have any... (1 Reply)
Am using a find command in my script .The output may be one or more. I need to store those values in a array and need to access those. Am unable to find the solution . Any help on this will be helpful.
if
< code>
else a=<find command output which gives the file name either 1 or more>
if 1... (1 Reply)
Hi all my very first post so go easy on me!!
I am trying to build a very simple script to list a file path with spaces in. But I can't get around this problem. My script is as follows:
#!/bin/bash
X="/Library/Users/Application\ Support/"
LS="ls"
AL="-al"
$LS $AL $X
The response I... (5 Replies)
(I am using bash)
I have a command that will find the line number in a file by searching for a string where it exists.
linenumber=$(grep -n "string" $FILENAME | cut -d : -fi)
This returns the line number and removes the string. Now that I have the line number I want to subtract 4 from it and... (5 Replies)
Hi All,
I was trying a shell script. I was unable to store file contents to a variable in the script. I have tried the below but unable to do it.
Input = `cat /path/op.diary`
Input = $(<op.diary)
I am using ksh shell. I want to store the 'op.diary' file contents to the variable 'Input'... (12 Replies)
Hi All,
I want to run multiple sql queries and store the data in variable but i want to use sql command only once. Is there a way without running sql command twice and storing.Please advise.
Eg :
Select 'Query 1 output' from dual;
Select 'Query 2 output' from dual;
I want to... (3 Replies)
Discussion started by: Rokkesh
3 Replies
LEARN ABOUT XFREE86
zgrep
ZGREP(1) General Commands Manual ZGREP(1)NAME
zgrep - search possibly compressed files for a regular expression
SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename...
DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code:
(-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the
standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep.
If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.
EXIT CODE
2 - An option that is not supported was specified.
AUTHOR
Charles Levert (charles@comm.polymtl.ca)
SEE ALSO grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)ZGREP(1)