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Full Discussion: Peculiar behavior due to IFS
Operating Systems Linux Peculiar behavior due to IFS Post 302786167 by ravisingh on Wednesday 27th of March 2013 03:41:48 AM
Old 03-27-2013
Code:
$ cat emp.lst
Rob Mills
Jack Thompson
Steffi Blues

a=`cat emp.lst`
echo $a

The output of this echo shows the 3 names in a single line which is perfectly fine.

But my doubt is with the below:
Code:
echo "$a"

The output of this shows the 3 names in 3 lines.
Please see, now also I expected the same output because the variable a is already defined. When above I defined the variable "a", the command cat emp.lst was not quoted and hence variable "a" should not have accepted a newline character.
But this output says that the var. "a" has accepted the newline character.
How come this happen?
 

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ECHO(1) 						    BSD General Commands Manual 						   ECHO(1)

NAME
echo -- write arguments to the standard output SYNOPSIS
echo [-n] [string ...] DESCRIPTION
The echo utility writes any specified operands, separated by single blank (' ') characters and followed by a newline (' ') character, to the standard output. The following option is available: -n Do not print the trailing newline character. This may also be achieved by appending 'c' to the end of the string, as is done by iBCS2 compatible systems. Note that this option as well as the effect of 'c' are implementation-defined in IEEE Std 1003.1-2001 (``POSIX.1'') as amended by Cor. 1-2002. Applications aiming for maximum portability are strongly encouraged to use printf(1) to sup- press the newline character. Some shells may provide a builtin echo command which is similar or identical to this utility. Most notably, the builtin echo in sh(1) does not accept the -n option. Consult the builtin(1) manual page. EXIT STATUS
The echo utility exits 0 on success, and >0 if an error occurs. SEE ALSO
builtin(1), csh(1), printf(1), sh(1) STANDARDS
The echo utility conforms to IEEE Std 1003.1-2001 (``POSIX.1'') as amended by Cor. 1-2002. BSD
April 12, 2003 BSD
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