03-21-2013
find /file directory/ -type d => list out all the directories (-type d) in /file directory/
grep file_name => finds the file_name from the list
$(command) => pretend the result of the command to be a variable
But I don't think this script will "get each file from their directory". You will have to change
-type d to
-type f then.
Best of Luck
![Smilie Smilie](https://www.unix.com/images/smilies/smile.gif)
This User Gave Thanks to PikK45 For This Post:
10 More Discussions You Might Find Interesting
1. UNIX for Dummies Questions & Answers
In Unix, How to find the file when i have the matter by subdirectory wise.
I have used the 'grep' command, but i can't get it, can anyone give the command of matter searched by subdirectorywise.
:confused: (5 Replies)
Discussion started by: anjanb2
5 Replies
2. Shell Programming and Scripting
I'm running a select statmenet from shell script, sometimes the result for the select is no rows selected. my question is, can I find a command in the shell asking about the result of the select and if the result is no data found print any msg I want instead of just writting no rows selected.... (3 Replies)
Discussion started by: aya_r
3 Replies
3. Shell Programming and Scripting
Can someone please explain the PS1="${x##*/}\$ " ??
how does that lop off leading components?
I don't understand it.. thanks
cd ( ) {
command cd "$@" Actually change directory
x=$(pwd) Get current directory name into variable x
PS1="${x##*/}\$ " ... (2 Replies)
Discussion started by: convenientstore
2 Replies
4. Shell Programming and Scripting
Hello, i am doing a project for school and i cannot figure out whats wrong with my 2 programs they dont seem to work at all.
the first program is called isprime and naturally it checks to see if hte number is prime or not
here is my code:
#!/usr/bin/bash
num=$1
echo you typed
if ... (2 Replies)
Discussion started by: jbou1087
2 Replies
5. UNIX for Dummies Questions & Answers
Suppose I have a script named "sc.sh"
in the script how to print out its name "sc.sh"? (3 Replies)
Discussion started by: meili100
3 Replies
6. UNIX for Dummies Questions & Answers
Hi All,
I am having this problem and I can't find a decent answer anywere.
I'am trying to perform multiple command in a shell script.
For example
mkdir test
tar cvzf test.tar.gz test/
rmdir test
The problem I get is that if I run this file as a cronjob, with a big "test" folder; the... (4 Replies)
Discussion started by: dswz
4 Replies
7. Programming
when i run a shell script i have to type
./my_prog
and the first line of my_prog has to have
#!/usr/bin/env bash
how do i change it to i only have to type my_prog to run it? (4 Replies)
Discussion started by: omega666
4 Replies
8. Homework & Coursework Questions
Use and complete the template provided. The entire template must be completed. If you don't, your post may be deleted!
1. The problem statement, all variables and given/known data:
Write a Bourne shell script which:
• Has one command line argument.
• If the command line argument is a... (5 Replies)
Discussion started by: abood1190
5 Replies
9. Shell Programming and Scripting
Hallo everyone,
I have this code:
DBNAME=DB_001 EXPORTPATH=./work EXPORTDATUM=${1} EXPORTSQL=$(dirname $0)/export_script.sql EXPORTSQL_TMP=${EXPORTPATH}/export.sql READYFILE=${EXPORTPATH}/ready EXPORTFILE_PREFIX=file.csv ## Prüfungen if ; then echo "not found" exit 1 fi
I am... (2 Replies)
Discussion started by: ratnalein88
2 Replies
10. Shell Programming and Scripting
I tried to run a command which simply generates SSH key with out prompting password.
After several trails , got the below command to run the script :
ssh-keygen -t rsa -N "" -f id_rsa
-N "" tells it to use an empty passphrase (the same as two of the enters in an interactive script)
-f... (0 Replies)
Discussion started by: ulaxmi
0 Replies
LEARN ABOUT PHP
finfo_file
FINFO_FILE(3) 1 FINFO_FILE(3)
finfo_file - Return information about a file
Procedural style
SYNOPSIS
string finfo_file NULL NULL (resource $finfo, string $file_name, [int $options = FILEINFO_NONE], [resource $context])
DESCRIPTION
Object oriented style string finfo::file NULL NULL (string $file_name, [int $options = FILEINFO_NONE], [resource $context])
This function is used to get information about a file.
PARAMETERS
o $finfo
- Fileinfo resource returned by finfo_open(3).
o $file_name
- Name of a file to be checked.
o $options
- One or disjunction of more Fileinfo constants.
o $context
- For a description of contexts, refer to "Stream Functions".
RETURN VALUES
Returns a textual description of the contents of the $file_name argument, or FALSE if an error occurred.
EXAMPLES
Example #1
A finfo_file(3) example
<?php
$finfo = finfo_open(FILEINFO_MIME_TYPE); // return mime type ala mimetype extension
foreach (glob("*") as $filename) {
echo finfo_file($finfo, $filename) . "
";
}
finfo_close($finfo);
?>
The above example will output something similar to:
text/html
image/gif
application/vnd.ms-excel
SEE ALSO
finfo_buffer(3).
PHP Documentation Group FINFO_FILE(3)