I thought
was only command to list files. Thanks for the information.
When I just do
It lists only one file and then the command prompt also comes on same line.
Whereas when I do
It list all files and command prompt comes on next line.
Could you please let me know the following:
1. When should we use
command instead of ls command.
2. Why the printf command I showed above list only one file. Where as
list all files.
3. I am not expecting any blank space in the file name that needs to be removed but incase blank space is part of the file name. Will it just not delete that file or will it mess up the server files in root directory or any other directories.
I want to run the 'locate' command and then remove what the command finds.
My guess was, locate blahblah |rm -f
but this does not work.
Thanks! (3 Replies)
Hi,
First time on the forum. I have converted some files using the Unix to DOS command but need to strip off the last record that is generated from this conversion that contains just a ^Z. Is there any command that would accomplish this without having to do stream editing? (4 Replies)
I have directory IXNPG7 under which i have seen file ads.c , ads.gif ,
ads.js and lots more with extension .html
I tried to remove the Entire Directory with rm -Rf IXNPG7
but it is saying -- Directory Not empty can't remove
Secondly i tried removing all the files first
using rm *.*... (7 Replies)
find /app01/tomcat_local -name *jsp* -type f -exec rm -r {} \;
I would assume the above is just deleting any *jsp* below the /app01/tomcat_local directory - is this correct as its seems to delete more than I expect.... (1 Reply)
Hi All,
Is there an option for 'rm' to "remove everything but these files"?
For instance if I have:
a.txt <-- I just want to remove this one
a_1.txt
a_2.txt
Is there an option ? for this:
rm -? *_*.txt
Thanks,
ScKaSx (4 Replies)
I have a file from which the Header and the Trailer lines need to be removed. They are confirmed to be the first and the last lines in the file.
I have tried a few commands, but not successful yet. It needs to be implemented urgently, hence any help is greatly appreciated.
Raghu
----------... (1 Reply)
I need to delete some files which are not getting removed not even from root user
-rw-r----- 1 ptml tellin 0 Jul 26 19:23 temp.out1
-rw-r----- 1 ptml tellin 0 Jul 26 19:23 temp.out
-rw-r----- 1 ptml tellin 2 Jul 26 19:23 prev
-rw-r----- 1... (4 Replies)
KSH
A simple remove command is not workin for me. The user has all the access and the return code after remove command is 0. But I am still able to find the file. I have the code as below.
tmplog=/tmp/$fl_nm.$$
main () {
--set of statments
rm -fr $tmplog
RC=$?
} (2 Replies)
hi,
I want to remove first word in all files where first and second word is seperated by comma.
example: a file contains Apple,mango.
i need only mango shoule be there in the file???
Apple, should be removed!!!!!
can anyone help me out???
thanks in advance,
Arun Manas:b: (2 Replies)
I have two questions:
the first is I have a line of code:
printf "What is the id of the patient getting GJB2 analysis : "; read id that stores a user input in a variable $id in the python directory c:/Users/cmccabe/Desktop/Python27/$id.txt
Using rm I get the error cannot remove ... (21 Replies)
Discussion started by: cmccabe
21 Replies
LEARN ABOUT CENTOS
shell-quote
SHELL-QUOTE(1) User Contributed Perl Documentation SHELL-QUOTE(1)NAME
shell-quote - quote arguments for safe use, unmodified in a shell command
SYNOPSIS
shell-quote [switch]... arg...
DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands
or files with embedded white space or shell globbing characters safely. Here are a few examples.
EXAMPLES
ssh preserving args
When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and
passes them to "$SHELL -c". This doesn't work as intended:
ssh host touch 'hi there' # fails
It creates 2 files, hi and there. Instead, do this:
cmd=`shell-quote touch 'hi there'`
ssh host "$cmd"
This gives you just 1 file, hi there.
process find output
It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to
split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote:
eval set -- `find -type f -print0 | xargs -0 shell-quote --`
debug shell scripts
shell-quote is better than echo for debugging shell scripts.
debug() {
[ -z "$debug" ] || shell-quote "debug:" "$@"
}
With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can.
save a command for later
shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command
you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are
things the user can't pass through), you can do something like this:
user_switches=
while [ $# != 0 ]
do
case x$1 in
x--pass-through)
[ $# -gt 1 ] || die "need an argument for $1"
user_switches="$user_switches "`shell-quote -- "$2"`
shift;;
# process other switches
esac
shift
done
# later
eval "shell-quote some-command $user_switches my args"
OPTIONS --debug
Turn debugging on.
--help
Show the usage message and die.
--version
Show the version number and exit.
AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions.
AUTHOR
Roderick Schertler <roderick@argon.org>
perl v5.16.3 2010-06-11 SHELL-QUOTE(1)