in order to find out the date of the files i have used the below code
ls|rev|cut -d "." -f2|cut -d "_" -f1|rev
this gives me the dates of all the files in the format ddmmyyyy.
now if i can change this to YYYYMMDD then my problem is solved. I would be able to bring the files which have this above calculated date greater than the last run date.
can this be done??
---------- Post updated at 01:27 PM ---------- Previous update was at 01:17 PM ----------
if the date can be changed to YYYYMMDD then i can use the code below to bring the relative files.
the something part needs to be completed...
Last edited by radoulov; 03-12-2013 at 07:17 AM..
Reason: Code tags fixed.
I would like to know how I could get a yesterday date in yyyymmdd e.g. today is 20011109, and I would like to get 20011108. Thank you!:confused: (2 Replies)
Okay, I have posted on here one other time and received very fast help, so I figured I'd post again.
Searched for awhile and couldn't find exactly what I'm looking for.
I am attempting to write a script that will search through a given directory, or search through the current directory, and... (10 Replies)
I have a file with some date columns in MM/DD/YYYY format:
SMPBR|DUP-DO NOT USE|NEW YORK||16105|BA5270715|6/6/2007 |MWERNER|109||||JOHN||SMITH|MD|72211118||||||74559|21 WILMINGTON RD||D|11/6/2003|SL# MD CONTACT-LIZ RICHARDS|||0|Y|N||1411458|
And I want to convert the date format to:
... (5 Replies)
In my shell script i have a variable which stores date in the format of YYYYMMDD. Is there any way to format this value to MM/DD/YYYY.
Thanks. (8 Replies)
Hi all,
i had a code where in user will enter a date in yyyymmdd format.. i didnt use any validation for the date and now the problem is if a user enters date instead of month after year it is proceeding with the code..
like if the date is 20120426 and if the user enters 20122604 it... (4 Replies)
Record:
Record1|Record2|Record3|Record4|Record5|DATE1|DATE2
Need to Check DATE1 & DATE2 is in DDMMYYYY format in a file.
records which not meet the date format DDMMYYYY extract to other file. (1 Reply)
Discussion started by: vivekn
1 Replies
LEARN ABOUT OPENSOLARIS
rev
rev(1) User Commands rev(1)NAME
rev - reverse the characters or lines of one or more files
SYNOPSIS
/usr/bin/rev [-l] [file ...]
DESCRIPTION
rev copies one or more files to standard output, reversing the order of characters on every line of the file.
OPTIONS
The following options are supported:
-l Reverse the order of the lines of the file, instead of characters.
--line
OPERANDS
The following operands are supported:
file Specifies the name of the file to use as input.
If file is not specified, or if file is a -, rev copies from standard input starting at the current offset.
EXIT STATUS
The following exit values are returned:
0 All files copied successfully.
>0 One or more files did not copy.
ATTRIBUTES
See attributes(5) for descriptions of the following attributes:
+-----------------------------+-----------------------------+
| ATTRIBUTE TYPE | ATTRIBUTE VALUE |
+-----------------------------+-----------------------------+
|Availability |SUNWcsu |
+-----------------------------+-----------------------------+
|CSI |Enabled |
+-----------------------------+-----------------------------+
|Interface Stability |Committed |
+-----------------------------+-----------------------------+
SEE ALSO cat(1), ksh93(1)tail(1), attributes(5)SunOS 5.11 27 Jan 2009 rev(1)