Hi,
I have file 1.txt with following entries as shown:
0152364|134444|10.20.30.40|015236433
0233654|122555|10.20.30.50|023365433
**
**
**
In file 2.txt I have the following entries as shown:
0152364|134444|10.20.30.40|015236433
0233654|122555|10.20.30.50|023365433... (4 Replies)
Hi all,
I'm looking for some help. I have a file (very long) that is organized like below:
>Cluster 0
0 283nt, >01_FRYJ6ZM12HMXZS... at +/99%
1 279nt, >01_FRYJ6ZM12HN12A... at +/99%
2 281nt, >01_FRYJ6ZM12HM4TS... at +/99%
3 283nt, >01_FRYJ6ZM12HM946... at +/99%
4 279nt,... (4 Replies)
Hi Guys,
Was trying to attempt the below using awk and sed, have no luck so far, so any help would be appreciated.
Current Text File: The first line has got an "\n", and the second line has got spaces/tabs then the word and "\n"
TIME SERVER/CLIENT TEXT... (6 Replies)
wondering if anyone has any thoughts to convert the below thru a shell script
Convert decimal signalling point notation to ANSI point code notation
There is a site that does that conversion but i need to implement the solution in a shell script.....Thoughts....
OS: Solaris 9
... (4 Replies)
Hello,
I want to simplify two commands into one.
1st command
$type_log_$instance.log.$date.0012nd command
$type_log.log.$date.tar.gzInto blue brackets, How do I do to replace the pattern by a blank or _$instance ?
$type_log?_$instance].log.$date.*Thank you. (13 Replies)
Hello
I have two kinds of logs like
server.logserver.log.2013-07-27.001i want to create a variable which look like this (with a pipe)
log_name=server.(log|log.$YYYY-MM-DD.)But i tried many cases but it didn't work.
Is it possible ? If yes, can you help me. (6 Replies)
hello folks,
I have few values in a log which are in scientific notation.
I am trying to convert into actual decimal format or integer but couldn't able to convert.
Values in scientific notation:
1.1662986666666665E-4
2.0946799999999998E-4
3.0741333333333333E-6
5.599999999999999E-7... (2 Replies)
'Hi
I'm using the following code to extract the lines(and redirect them to a txt file) after the pattern match. But the output is inclusive of the line with pattern match.
Which option is to be used to exclude the line containing the pattern?
sed -n '/Conn.*User/,$p' > consumers.txt (11 Replies)
The sample file:
dept1: user1,user2,user3
dept2: user4,user5,user6
dept3: user7,user8,user9
I want to match by '/^dept2.*/' but don't want to have substring 'dept2:' in output. How to compose such regex? (8 Replies)
Discussion started by: urello
8 Replies
LEARN ABOUT PHP
datetime.setdate
DATETIME.SETDATE(3) 1 DATETIME.SETDATE(3)DateTime::setDate - Sets the date
Object oriented style
SYNOPSIS
public DateTime DateTime::setDate (int $year, int $month, int $day)
DESCRIPTION
Procedural style
DateTime date_date_set (DateTime $object, int $year, int $month, int $day)
Resets the current date of the DateTime object to a different date.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $year
- Year of the date.
o $month
- Month of the date.
o $day
- Day of the date.
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
CHANGELOG
+--------+---------------------------------------------------+
|Version | |
| | |
| | Description |
| | |
+--------+---------------------------------------------------+
| 5.3.0 | |
| | |
| | Changed the return value on success from NULL to |
| | DateTime. |
| | |
+--------+---------------------------------------------------+
EXAMPLES
Example #1
DateTime.setDate(3) example
Object oriented style
<?php
$date = new DateTime();
$date->setDate(2001, 2, 3);
echo $date->format('Y-m-d');
?>
Procedural style
<?php
$date = date_create();
date_date_set($date, 2001, 2, 3);
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2001-02-03
Example #2
Values exceeding ranges are added to their parent values
<?php
$date = new DateTime();
$date->setDate(2001, 2, 28);
echo $date->format('Y-m-d') . "
";
$date->setDate(2001, 2, 29);
echo $date->format('Y-m-d') . "
";
$date->setDate(2001, 14, 3);
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-02-28
2001-03-01
2002-02-03
SEE ALSO DateTime.setISODate(3), DateTime.setTime(3).
PHP Documentation Group DATETIME.SETDATE(3)