I need to print the lines that do not match a pattern. I tried using grep -v and sed -n '/pattern/!p', but both of them are not working as I am passing the pattern as variable and it can be null some times.
Example
would need the output to be not matching pattern 1234, so it would be
The value in the brackets is passed as a variable and sometimes it can be null
so the grep or sed is not returning any value. when it is supposed to.
Please help.
Last edited by radoulov; 03-06-2013 at 12:44 PM..
Reason: Code tags.
Hi
I have a file (say 'file1')and I want to search for a first occurence of pattern (say 'ERROR') and print ten lines in the file below pattern. I have to code it in PERL and I am using Solaris 5.9.
I appreciate any help with code
Thanks
Ammu (6 Replies)
Hi All,
Please find the sample file below:
NAME ID NUMBER
-------------------------------------------------------------------------------------------------- ---------
abcdefgheija;lksdf ... (13 Replies)
I have in a file
domain.com. 1909 IN A 1.22.33.44
domain.com. 1909 IN A 22.33.44.55
ns1.domain.com. 1699 IN A 33.44.55.66
ns2.domain.com. 1806 IN A 77.77.66.66
I need to "grep" or "awk" out the lines starting with domain.com. as follows.
domain.com. 1909 IN A 1.22.33.44
domain.com.... (3 Replies)
I am using Solaris, I want to print
3 lines before pattern match
pattern
5 lines after pattern match
Pattern is abcd to be searched in a.txt. Looking for the solution in sed/awk/perl. Thanks ..
Input File a.txt:
=================
1
2
3
abcd
4
5
6
7
8 (7 Replies)
Data:
Pattern Data Data Data
Data Data Data
Data Data Data
...
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