Hi all,
I have an awk basic question.
file.text
Our Location:
Our home has light yellow siding,
and is a duplex on Main Street,
across from the High School,
and across the lane from the Health Center
If I run:
cat file.txt | awk '{print $2}' | grep... (7 Replies)
I have a script problem that I am not able to solve due my very limited understanding of unix/awk.
This is the contents of test.sh
awk '{print $1}'
From the prompt if I enter:
./test.sh Hello World
I would expect to see "Hello" but all I get is a blank line. Only then if I enter "Hello... (2 Replies)
I find an script with awk sitting around. I went through some online manuals, but I can't figure out exactly how it works. I can't post the whole program. Not allowed.
This is the line that is confusing me. I get when else is in the script
grep -v "^REM " $1| grep -v "JUNK;" | awk -F" "... (2 Replies)
Here's a basic awk program I am trying to run. It shows no error but shows no result either too. If someone can look up and tell me what's wrong I will be obliged.
Thanks. :)
Code Snippet.
#!/bin/bash
awk '{
for (i = 1 ; i <= 3 ; i++)
for ( j = 1 ; j <= 3 ; j++ ) {
... (2 Replies)
Hi,
Sorry if this is a newbie question. I guess you can use either awk or shell script for this sequence of operations, but knowing very little about either of them I'm not sure how I should try to write this.
The basic objective is to copy certain files that are scattered all over my... (10 Replies)
Hi,
I was trying to change the value of the 4th column (put '1' in the 4th column of each row). My awk command is:
awk -F, '{$3=1;}1' OFS= input.txt > ./test_out.txt
My input file is:
a 1 2 31
b 4 5 61
c 7 8 91
My output file (test_out.txt)is:
a 1 2 31
b 4 5 61
c 7 8 91
What... (4 Replies)
input:
Name|Operation
rec_10|1+2+2-
Output:
rec_10|1
Basically I am trying to calculate the result of "the path" in $3 where the operators follow the number and not preceding them like we normally do:
rec_10: +1+2-2=1
But I realise (I am sure there is a good reason for that) that awk... (7 Replies)
1. increase file space
first, double space a file:
awk '1;{print ""}'
I probably can understand it:print a blank line every time.But when I read triple space a file I am confused:
awk '1;{print "\n"}'
doesn't it meaning print a blank line every time too?
2. number each line of file, but... (6 Replies)
Discussion started by: hhdzhu
6 Replies
LEARN ABOUT DEBIAN
devel::refcount
Devel::Refcount(3pm) User Contributed Perl Documentation Devel::Refcount(3pm)NAME
"Devel::Refcount" - obtain the REFCNT value of a referent
SYNOPSIS
use Devel::Refcount qw( refcount );
my $anon = [];
print "Anon ARRAY $anon has " . refcount($anon) . " reference
";
my $otherref = $anon;
print "Anon ARRAY $anon now has " . refcount($anon) . " references
";
DESCRIPTION
This module provides a single function which obtains the reference count of the object being pointed to by the passed reference value.
FUNCTIONS
$count = refcount($ref)
Returns the reference count of the object being pointed to by $ref.
COMPARISON WITH SvREFCNT
This function differs from "Devel::Peek::SvREFCNT" in that SvREFCNT() gives the reference count of the SV object itself that it is passed,
whereas refcount() gives the count of the object being pointed to. This allows it to give the count of any referent (i.e. ARRAY, HASH,
CODE, GLOB and Regexp types) as well.
Consider the following example program:
use Devel::Peek qw( SvREFCNT );
use Devel::Refcount qw( refcount );
sub printcount
{
my $name = shift;
printf "%30s has SvREFCNT=%d, refcount=%d
",
$name, SvREFCNT($_[0]), refcount($_[0]);
}
my $var = [];
printcount 'Initially, $var', $var;
my $othervar = $var;
printcount 'Before CODE ref, $var', $var;
printcount '$othervar', $othervar;
my $code = sub { undef $var };
printcount 'After CODE ref, $var', $var;
printcount '$othervar', $othervar;
This produces the output
Initially, $var has SvREFCNT=1, refcount=1
Before CODE ref, $var has SvREFCNT=1, refcount=2
$othervar has SvREFCNT=1, refcount=2
After CODE ref, $var has SvREFCNT=2, refcount=2
$othervar has SvREFCNT=1, refcount=2
Here, we see that SvREFCNT() counts the number of references to the SV object passed in as the scalar value - the $var or $othervar
respectively, whereas refcount() counts the number of reference values that point to the referent object - the anonymous ARRAY in this
case.
Before the CODE reference is constructed, both $var and $othervar have SvREFCNT() of 1, as they exist only in the current lexical pad. The
anonymous ARRAY has a refcount() of 2, because both $var and $othervar store a reference to it.
After the CODE reference is constructed, the $var variable now has an SvREFCNT() of 2, because it also appears in the lexical pad for the
new anonymous CODE block.
PURE-PERL FALLBACK
An XS implementation of this function is provided, and is used by default. If the XS library cannot be loaded, a fallback implementation in
pure perl using the "B" module is used instead. This will behave identically, but is much slower.
Rate pp xs
pp 225985/s -- -66%
xs 669570/s 196% --
SEE ALSO
o Test::Refcount - assert reference counts on objects
AUTHOR
Paul Evans <leonerd@leonerd.org.uk>
perl v5.14.2 2011-11-15 Devel::Refcount(3pm)