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Full Discussion: Basic awk help
Top Forums UNIX for Dummies Questions & Answers Basic awk help Post 302774711 by sectech on Sunday 3rd of March 2013 12:52:24 AM
Old 03-03-2013
Basic awk help

Im sure this is an easy question, but Ive tried and tried to get this to print all on one line and cant figure out why its not, so maybe someone can help
Code:
awk '/AP/{sub(/:80/, "", $4);printf $4"\t"} /User-Agent/{sub(/^[^:][^:]*:/,"");print};sub(/\.80/,"", $4);/Host/{sub(/^[^:][^:]*:/,""); print}'

What this prints is "AP" then "User-Agent" on one line(good) but then prints "HOST" on a separate line? How can I get all three to print on a single line?

Thanks!Smilie

Last edited by sectech; 03-03-2013 at 01:58 AM..
 

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PRINT(3)								 1								  PRINT(3)

print - Output a string

SYNOPSIS
int print (string $arg) DESCRIPTION
Outputs $arg. print is not actually a real function (it is a language construct) so you are not required to use parentheses with its argument list. PARAMETERS
o $arg - The input data. RETURN VALUES
Returns 1, always. EXAMPLES
Example #1 print examples <?php print("Hello World"); print "print() also works without parentheses."; print "This spans multiple lines. The newlines will be output as well"; print "This spans multiple lines. The newlines will be output as well."; print "escaping characters is done "Like this"."; // You can use variables inside a print statement $foo = "foobar"; $bar = "barbaz"; print "foo is $foo"; // foo is foobar // You can also use arrays $bar = array("value" => "foo"); print "this is {$bar['value']} !"; // this is foo ! // Using single quotes will print the variable name, not the value print 'foo is $foo'; // foo is $foo // If you are not using any other characters, you can just print variables print $foo; // foobar print <<<END This uses the "here document" syntax to output multiple lines with $variable interpolation. Note that the here document terminator must appear on a line with just a semicolon no extra whitespace! END; ?> NOTES
Note Because this is a language construct and not a function, it cannot be called using variable functions. SEE ALSO
echo(3), printf(3), flush(3), Heredoc syntax. PHP Documentation Group PRINT(3)
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