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Top Forums Shell Programming and Scripting What is wrong with my script? Post 302774685 by jim mcnamara on Saturday 2nd of March 2013 10:45:07 PM
Old 03-02-2013
You cannot embed shell variables in an awk statement that way.
Generally
Code:
var=foo
awk -v myvar=$var '{.....}' somefile

-v [awkvariable name]=$variable

It looks like you are trying to get a substring of a variable. Some shells like bash provide that.

Code:
${string:position:length}

example:
Code:
a=123456789
len=${#a}   # length of the variable
len=$(( $len -1 4 ))
echo ${a:0:len}   # get string minus 4 characters

It is much less efficient in awk, but you can it this way (one of several) if you are not using the bash shell:
Code:
var=123456789
newvar=$(echo "$s" | awk  '{print substr($0,1,length($0)-4) }')

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IGAWK(1)							 Utility Commands							  IGAWK(1)

NAME
igawk - gawk with include files SYNOPSIS
igawk [ all gawk options ] -f program-file [ -- ] file ... igawk [ all gawk options ] [ -- ] program-text file ... DESCRIPTION
Igawk is a simple shell script that adds the ability to have ``include files'' to gawk(1). AWK programs for igawk are the same as for gawk, except that, in addition, you may have lines like @include getopt.awk in your program to include the file getopt.awk from either the current directory or one of the other directories in the search path. OPTIONS
See gawk(1) for a full description of the AWK language and the options that gawk supports. EXAMPLES
cat << EOF > test.awk @include getopt.awk BEGIN { while (getopt(ARGC, ARGV, "am:q") != -1) ... } EOF igawk -f test.awk SEE ALSO
gawk(1) Effective AWK Programming, Edition 1.0, published by the Free Software Foundation, 1995. AUTHOR
Arnold Robbins (arnold@skeeve.com). Free Software Foundation Nov 3 1999 IGAWK(1)
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