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Top Forums UNIX for Dummies Questions & Answers How to return only specific words in a line? Post 302772672 by Yoda on Tuesday 26th of February 2013 11:44:30 AM
Old 02-26-2013
Quote:
Originally Posted by angad.makkar
egrep "idxxx1|idxxx3" file | awk '{print $1 "\t" $4}' | awk -F';' '{print $1}'
Please note that there is no need to use egrep or grep with awk because awk is capable of doing what grep or egrep can do thus you can save a pipeline.

Here is another approach:
Code:
awk '/^idxxx1/||/^idxxx3/{$0=$1" "$NF;sub(/;.*/,x); print}' file

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ZGREP(1)						    BSD General Commands Manual 						  ZGREP(1)

NAME
zgrep, zegrep, zfgrep -- print lines matching a pattern in gzip-compressed files SYNOPSIS
zgrep [grep-flags] [--] pattern [files ...] zegrep [grep-flags] [--] pattern [file ...] zfgrep [grep-flags] [--] pattern [file ...] DESCRIPTION
zgrep runs grep(1) on files or stdin, if no files argument is given, after decompressing them with zcat(1). The grep-flags and pattern arguments are passed on to grep(1). If an -e flag is found in the grep-flags, zgrep will not look for a pattern argument. zegrep calls egrep(1), while zfgrep calls fgrep(1). EXIT STATUS
In case of missing arguments or missing pattern, 1 will be returned, otherwise 0. SEE ALSO
egrep(1), fgrep(1), grep(1), gzip(1), zcat(1) AUTHORS
Thomas Klausner <wiz@NetBSD.org> BSD
December 28, 2003 BSD
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