Grep and Print Post: 302771642

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1. Shell Programming and Scripting

to grep and print their counts

suppose u have a file ACFCFACCACARCSHFARCVJVASTVAJFTVAJVGHBAJ another file A C F R then output shud be A= 9 C=7 F=3 R=2 Thanks

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using grep and print filename

Hi, I have a question on bash. Basically I would like to print a file name using bash. I am actually trying to grep a particular character in sequential files. I have alot files such that a.txt, b.txt,c.txt...etc. If I found a certain character, I would print that particular filename. I...

3. Shell Programming and Scripting

Print lines after grep

Hi all, I need help in following scenario. I have a file with about 10,000 lines. There are several lines which have word "START" (all upper case) in them. I want to grep line with word "START" and then do the following 1. Print the line number having word "START" 2. Print the next 11 lines. ...

4. Shell Programming and Scripting

MEM=`ps v $PPID| grep -i db2 | grep -v grep| awk '{ if ( $7 ~ " " ) { print 0 } else

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Grep & print

I just need to print value 12 digit number after the key *MI*. My big concern is the below lines are not fixed format or length so cant cut based on the position. XSA*00**00**XZ*DA-Paper*30*942411167****MI*010001990802~AEE XSA*00**00**ZZ*EA-aper*30*94169****MI*010001960802~SDRE*ER...

6. Shell Programming and Scripting

Print lines before and after..not grep -A

Hi I have this in my file 2011-04-18 15:32:11 system-alert-00012: UDP flood! From xxxxxx to yyyyyyyyyy, int ethernet0/2). Occurred 1 times. 2011-04-18 15:32:11 system-alert-00012: UDP flood! From xxxxxx to yyyyyyyyyy, int ethernet0/2). Occurred 1 times. 2011-04-18 15:32:11...

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Grep syntax print after certain character

My current code is: user@ubuntu:~/Desktop$ grep -e "$packaged by$\|$employee$\|$file name$\|$Total Data (MB) Read$\|$Begin Time$" log.txt packaged by = Ron Mexico employee = Michael Vick file name = Mike_Vick_2011.bat Total Data (MB) Read: 11.82 Begin Time: 6/13/2011...

8. Shell Programming and Scripting

Grep for the string and then print the next 4 lines

RHEL 5.8 I have a text file like below. I want to grep for a string and then print the next 4 lines including the line with the string I grepped for For eg: I want grep for the string HANS and then print the next 4 lines including HANS $ cat someText.txt JOHN NATIONALITY:...

LEARN ABOUT MINIX

grep

GREP(1) 						      General Commands Manual							   GREP(1)

NAME

       grep - search a file for lines containing a given pattern

SYNOPSIS

       grep [-elnsv] pattern [file] ...

OPTIONS

       -e     -e pattern is the same as pattern

       -c     Print a count of lines matched

       -i     Ignore case

       -l     Print file names, no lines

       -n     Print line numbers

       -s     Status only, no printed output

       -v     Select lines that do not match

EXAMPLES

       grep mouse file	   # Find lines in file containing mouse

       grep [0-9] file	   # Print lines containing a digit

DESCRIPTION

       Grep  searches  one  or	more  files (by default, stdin) and selects out all the lines that match the pattern.  All the regular expressions
       accepted by ed and mined are allowed.  In addition, + can be used instead of * to mean 1 or more occurrences, ? can be used to mean 0 or  1
       occurrences,  and  |  can  be used between two regular expressions to mean either one of them.  Parentheses can be used for grouping.  If a
       match is found, exit status 0 is returned.  If no match is found, exit status 1 is returned.  If an error is detected,  exit  status  2	is
       returned.

SEE ALSO

       cgrep(1), fgrep(1), sed(1), awk(9).

																	   GREP(1)