Say I write something like the following:
var1=1
var2=2
for int in 1 2
do
echo "\$var$int"
done
I want the output to be:
1
2
Instead I get something like:
$var1
$var2 (2 Replies)
in a text " Korn Shell Unix programming Manual 3° Edition"
i have found this sintax to declare a compoud variable:
variable=(
fild1
fild1
)
but this sintax in ksh and sh (HP-UNIX) not work...
why?? exist another solution for this type of variable ??? (5 Replies)
I am using two shell scripts a.ksh and b.ksh
a.ksh
1. Sets the value
+++++++++++++++++
export USER1=abcd1
export PASSWORD=xyz
+++++++++++++++++
b.ksh
2. Second scripts calls sctipt a.ksh and uses the values set in a.ksh and pass to an executable demo... (2 Replies)
Hi
I have the following block of code in korn shell and don't now how to refer to variable `print variable1.$dvd` ?
---
integer dvd=4
integer number=0
while (( dvd!=0 ))
do
print "Iteracja numer : $dvd"
print "$_" #it refers to $dvd var but want to refer... (3 Replies)
this is my issue.
4 parameters are passed from korn shell to sql script.
parameter_1= varchar2 datatype or no value entered my user.
parameter_2= number datatype or no value entered my user.
parameter_3= number datatype or no value entered my user.
parameter_4= number datatype or no... (5 Replies)
Simple enough problem I think, I just can't seem to get it right.
The below doesn't work as intended, it's just a function defined in a much larger script:
CheckValues() {
for field in \
Group_ID \
Group_Title \
Rule_ID \
Rule_Severity \
... (2 Replies)
Hi
I am using two shell scripts which are running on the system simultaneously. And in one of the script i am exporting an Integer Variable.
Now i want to use the variable in another script. But i cannot run the first script in the second as the first script has many other functions which... (3 Replies)
I have following files at /dir1
a.csv.20131201
b.csv.20131201
c.csv.20131201
d.csv.20131201
a.csv.20131202
b.csv.20131202
c.csv.20131202
d.csv.20131202
.......................
.......................
.......................
.......................
I need to move these files to... (4 Replies)
I have written a script which will take input parameter as another script.
However, if the script passed as input parameter has parameters then this script doesn't work.
I have a script b.ksh which has 1 and 2 as parameters
I have a script c.ksh which has 3,4 and 5 as parameters
vi a.ksh... (1 Reply)
Discussion started by: Vee
1 Replies
LEARN ABOUT DEBIAN
devel::refcount
Devel::Refcount(3pm) User Contributed Perl Documentation Devel::Refcount(3pm)NAME
"Devel::Refcount" - obtain the REFCNT value of a referent
SYNOPSIS
use Devel::Refcount qw( refcount );
my $anon = [];
print "Anon ARRAY $anon has " . refcount($anon) . " reference
";
my $otherref = $anon;
print "Anon ARRAY $anon now has " . refcount($anon) . " references
";
DESCRIPTION
This module provides a single function which obtains the reference count of the object being pointed to by the passed reference value.
FUNCTIONS
$count = refcount($ref)
Returns the reference count of the object being pointed to by $ref.
COMPARISON WITH SvREFCNT
This function differs from "Devel::Peek::SvREFCNT" in that SvREFCNT() gives the reference count of the SV object itself that it is passed,
whereas refcount() gives the count of the object being pointed to. This allows it to give the count of any referent (i.e. ARRAY, HASH,
CODE, GLOB and Regexp types) as well.
Consider the following example program:
use Devel::Peek qw( SvREFCNT );
use Devel::Refcount qw( refcount );
sub printcount
{
my $name = shift;
printf "%30s has SvREFCNT=%d, refcount=%d
",
$name, SvREFCNT($_[0]), refcount($_[0]);
}
my $var = [];
printcount 'Initially, $var', $var;
my $othervar = $var;
printcount 'Before CODE ref, $var', $var;
printcount '$othervar', $othervar;
my $code = sub { undef $var };
printcount 'After CODE ref, $var', $var;
printcount '$othervar', $othervar;
This produces the output
Initially, $var has SvREFCNT=1, refcount=1
Before CODE ref, $var has SvREFCNT=1, refcount=2
$othervar has SvREFCNT=1, refcount=2
After CODE ref, $var has SvREFCNT=2, refcount=2
$othervar has SvREFCNT=1, refcount=2
Here, we see that SvREFCNT() counts the number of references to the SV object passed in as the scalar value - the $var or $othervar
respectively, whereas refcount() counts the number of reference values that point to the referent object - the anonymous ARRAY in this
case.
Before the CODE reference is constructed, both $var and $othervar have SvREFCNT() of 1, as they exist only in the current lexical pad. The
anonymous ARRAY has a refcount() of 2, because both $var and $othervar store a reference to it.
After the CODE reference is constructed, the $var variable now has an SvREFCNT() of 2, because it also appears in the lexical pad for the
new anonymous CODE block.
PURE-PERL FALLBACK
An XS implementation of this function is provided, and is used by default. If the XS library cannot be loaded, a fallback implementation in
pure perl using the "B" module is used instead. This will behave identically, but is much slower.
Rate pp xs
pp 225985/s -- -66%
xs 669570/s 196% --
SEE ALSO
o Test::Refcount - assert reference counts on objects
AUTHOR
Paul Evans <leonerd@leonerd.org.uk>
perl v5.14.2 2011-11-15 Devel::Refcount(3pm)