Now there's just the challenge of getting the number of seconds out of that string. I'm guessing it may vary, not printing days if it hasn't been up days, etc... hmm...
Hello gurus,
I need to write a script to find out all the file that got changed on a specific folder since a given input date (Date to be given as Input)
Thanx (1 Reply)
Hi, I have a directory PRIVATE in which I have several directories and each of these have several files. Therefore, I need to find those files by size and date to back up those files in another directory.
I don't know how to implement this shell script using ''find''.
appreciate any... (1 Reply)
Hi,
I have a text file, foo.txt, it looks something like below. In the file there is a line that gives the date in the form of: Mon Jun 15 11:09:31 2008. I need to find which date is the newest and then store certain details of that list data to another file. So, in this sample text file, I... (6 Replies)
I set up remote printing on a clients Unix server to my Windows XP USB printer. My USB printer is connected directly to my PC (no print server and no network input on printer). With my Win XP PC connected to my cable modem (without the router), i can do
lp -dhp842c /etc/hosts and it prints. I... (7 Replies)
Hi Experts,
i am using the below code get the date of previous day.
#!/usr/bin/ksh
datestamp=`date '+%Y%m%d'`
yest=$((datestamp -1))
echo $yest
When i execute the code i am getting output as:
20130715
What i am trying here is, based on the date passed i am fetching previus day's... (0 Replies)
How can i trace a destination IP from the initiating IP to see what router(s) it goes thru from the source IP to the destination IP on Linux Redhat server? If it is the traceroute command, what options can i Use to get that infoirmation?
Thanks (2 Replies)
Hi,
I have parameter file wo_location.prm which has a date variable $last_upd_date= 02032016.
I need to write a unix shell script to find that variable and increment it by 1 day.
The path to the file is root/dir_lc/shared/param/wo_location.prm and the variable is $last_upd_date.
Any... (2 Replies)
Hi All,
Could you please provide the shell script to find number of weekdays and
number of weekends for a given date for that month.
Monday to friday should be considered as weekdays and Saturday and Sunday should be considered as weekends.
Date should be passed as parameter.
For... (13 Replies)
Discussion started by: ROCK_PLSQL
13 Replies
LEARN ABOUT OSX
time::seconds
Time::Seconds(3pm) Perl Programmers Reference Guide Time::Seconds(3pm)NAME
Time::Seconds - a simple API to convert seconds to other date values
SYNOPSIS
use Time::Piece;
use Time::Seconds;
my $t = localtime;
$t += ONE_DAY;
my $t2 = localtime;
my $s = $t - $t2;
print "Difference is: ", $s->days, "
";
DESCRIPTION
This module is part of the Time::Piece distribution. It allows the user to find out the number of minutes, hours, days, weeks or years in a
given number of seconds. It is returned by Time::Piece when you delta two Time::Piece objects.
Time::Seconds also exports the following constants:
ONE_DAY
ONE_WEEK
ONE_HOUR
ONE_MINUTE
ONE_MONTH
ONE_YEAR
ONE_FINANCIAL_MONTH
LEAP_YEAR
NON_LEAP_YEAR
Since perl does not (yet?) support constant objects, these constants are in seconds only, so you cannot, for example, do this: "print
ONE_WEEK->minutes;"
METHODS
The following methods are available:
my $val = Time::Seconds->new(SECONDS)
$val->seconds;
$val->minutes;
$val->hours;
$val->days;
$val->weeks;
$val->months;
$val->financial_months; # 30 days
$val->years;
$val->pretty; # gives English representation of the delta
The usual arithmetic (+,-,+=,-=) is also available on the objects.
The methods make the assumption that there are 24 hours in a day, 7 days in a week, 365.24225 days in a year and 12 months in a year.
(from The Calendar FAQ at http://www.tondering.dk/claus/calendar.html)
AUTHOR
Matt Sergeant, matt@sergeant.org
Tobias Brox, tobiasb@tobiasb.funcom.com
BalieXXzs SzabieXX (dLux), dlux@kapu.hu
LICENSE
Please see Time::Piece for the license.
Bugs
Currently the methods aren't as efficient as they could be, for reasons of clarity. This is probably a bad idea.
perl v5.16.2 2012-10-11 Time::Seconds(3pm)