awk to print first row with forth column and last row with fifth column in each file
file with this content
Quote:
PPP11 OFS HIGH 1200 1401 + 0 KNOW
PPP22 OFS HIGH 1433 1588 - 2 KNOW
Quote:
u want to print first row with fourth column and second row with fifth column; the code is below
The error is shown with syntax error; what can be done
Quote:
And another question is that if there is to print first row with fourth column and last row with fifth column; in each file; how the solution with awk will be?
Hi,
I want to write a shell script which increments a particular column in a row from a text file and then adds another row below the current row with the incremented value .
For Eg .
if the input file has a row :
abc xyz lmn 89 lm nk o p
I would like the script to create something like... (9 Replies)
Hello,
I have an input file like the following:
11_3_4
2_1_35
3_15__
_16989
Where '_' is a space. The data is in a table. Is there a way for the program to prompt the user for x1,y1 and x2,y2, where x1,y1 is the desired number (for example x=6 y=4 is a value of 4) and move to a desired spot... (2 Replies)
Hi, Please read the whole thread.
I have been working on this script below. It works fine, feel free to copy and test with the INPUT File below as well.
example:
PACKET DATA PROTOCOL CONTEXT DATA
APNID PDPADD EQOSID VPAA PDPCH PDPTY PDPID
10 ... (6 Replies)
Hi Friends,
I have a single column data like below.
1
2
3
4
5
I need the output like below.
0
1
2
3
4
where each row (including first row) subtracting from first row and the result should print below like the way shown in output file.
Thanks
Sid (11 Replies)
Hi all
I have file with columns
F3 pathway CPS
F2
H2
H4
H5
H6 no pathway CMP
H7
H8
H9
H10
My expected output is
F3 pathway CPS
F2 pathway CPS (10 Replies)
I have a table with this structure:
cola colb colc
1 19 lemon
20 31 lemon
32 100 lemon
159 205 cherries
210 500 cherries
and need to parse it into this format:
cola colb colc
1 100 lemon
159 500 cherries
So I need the first row of cola and the last row of colb if colc has the... (3 Replies)
Hi,
I have a comma separated file. I would like to print every alternate columns into a new row.
Example input file:
Name : John, Age : 30, DOB : 30-Oct-2018
Example output:
Name,Age,DOB
John,30,30-Oct-2018 (3 Replies)
Discussion started by: Lini
3 Replies
LEARN ABOUT DEBIAN
shell-quote
SHELL-QUOTE(1p) User Contributed Perl Documentation SHELL-QUOTE(1p)NAME
shell-quote - quote arguments for safe use, unmodified in a shell command
SYNOPSIS
shell-quote [switch]... arg...
DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands
or files with embedded white space or shell globbing characters safely. Here are a few examples.
EXAMPLES
ssh preserving args
When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and
passes them to "$SHELL -c". This doesn't work as intended:
ssh host touch 'hi there' # fails
It creates 2 files, hi and there. Instead, do this:
cmd=`shell-quote touch 'hi there'`
ssh host "$cmd"
This gives you just 1 file, hi there.
process find output
It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to
split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote:
eval set -- `find -type f -print0 | xargs -0 shell-quote --`
debug shell scripts
shell-quote is better than echo for debugging shell scripts.
debug() {
[ -z "$debug" ] || shell-quote "debug:" "$@"
}
With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can.
save a command for later
shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command
you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are
things the user can't pass through), you can do something like this:
user_switches=
while [ $# != 0 ]
do
case x$1 in
x--pass-through)
[ $# -gt 1 ] || die "need an argument for $1"
user_switches="$user_switches "`shell-quote -- "$2"`
shift;;
# process other switches
esac
shift
done
# later
eval "shell-quote some-command $user_switches my args"
OPTIONS --debug
Turn debugging on.
--help
Show the usage message and die.
--version
Show the version number and exit.
AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions.
AUTHOR
Roderick Schertler <roderick@argon.org>
perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)