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Top Forums Programming Efficient logging of time measurements Post 302767685 by venam on Thursday 7th of February 2013 08:21:07 AM
Old 02-07-2013
I think because you are using a binary struct it will write the data as a reserved block in the pipe and you won't need mutex because the data won't overlap.
I may be wrong about that.
 

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STRUCT 
PIPE_INODE_IN(9) pipes API STRUCT PIPE_INODE_IN(9) NAME
struct_pipe_inode_info - a linux kernel pipe SYNOPSIS
struct pipe_inode_info { struct mutex mutex; wait_queue_head_t wait; unsigned int nrbufs; unsigned int curbuf; unsigned int buffers; unsigned int readers; unsigned int writers; unsigned int files; unsigned int waiting_writers; unsigned int r_counter; unsigned int w_counter; struct page * tmp_page; struct fasync_struct * fasync_readers; struct fasync_struct * fasync_writers; struct pipe_buffer * bufs; }; MEMBERS
mutex mutex protecting the whole thing wait reader/writer wait point in case of empty/full pipe nrbufs the number of non-empty pipe buffers in this pipe curbuf the current pipe buffer entry buffers total number of buffers (should be a power of 2) readers number of current readers of this pipe writers number of current writers of this pipe files number of struct file refering this pipe (protected by ->i_lock) waiting_writers number of writers blocked waiting for room r_counter reader counter w_counter writer counter tmp_page cached released page fasync_readers reader side fasync fasync_writers writer side fasync bufs the circular array of pipe buffers COPYRIGHT
Kernel Hackers Manual 3.10 June 2014 STRUCT PIPE_INODE_IN(9)
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